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Inserting a single DB line within a foreach statement

Posted on 2009-04-08
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Last Modified: 2012-05-06
Hi Experts,
I have a form where members can upload a file, I have created a parser to grab the information from the file perfectly. My problem is, my data is currently being displayed via a foreach statement (code in below snippet).

Rather than echoing the data to the screen, I want to save the data in my database as a single line only to save from having to process the file each time. If I put an insert within the foreach statement its obviously going to create more than 1 DB insert.

The values being displayed on the page here is what i need to catch in a single statement:-
echo 'player with no team: <br />';
echo 'player in team '.$k.'<br />';
echo 'Player Name:'.$player['name'].'; IP: '.$player['ip'].'; Army: '.$n->getArmyName($player['army']).'

Can anyone help?
Thanks in advance
$n = new $classname();
    if (!$n->parse($_FILES['some_identifier']['tmp_name'])) {
        die('can not read it somehow');
    }
    $teams = $n->getTeams();
    foreach($teams as $k => $team) {
        if ($k == 0) { // team 0 store the player without team
            echo 'player with no team: <br />';
        } else {
            echo 'player in team '.$k.'<br />';
        }
        foreach ($team as $k_p => $player) {
            echo 'Player Name:'.$player['name'].'; IP: '.$player['ip'].'; Army: '.$n->getArmyName($player['army']).'<br />';
        }

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Question by:EzEApostle
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2 Comments
 
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Expert Comment

by:QualitySoftwareDevelopment
ID: 24095076
You can make it as this (if I get the meaning right ;-))


$sql="INSERT INTO table_name (field1, field2, field3) VALUES (";
 
//make your first datacollect
$sql.=$datacollect.", ";
 
//make your second datacollect
$sql.=$datacollect.", ";
 
//make your third datacollect
$sql.=$datacollect."); ";

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Accepted Solution

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QualitySoftwareDevelopment earned 500 total points
ID: 24095087
and if you need more inserts in one line you can do like this:

$sql = "INSERT INTO table_name (field1, filed2, field3)
  VALUES
  ($data1, $data2, $data3),
  ($data1, $data2, $data3),
  ($data1, $data2, $data3),
  ($data1, $data2, $data3)";

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