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How can I launch my application inside another application in MFC

Posted on 2009-04-08
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Last Modified: 2013-11-20
Experts,

What is the simplest or easiest technique for launching one of my applications inside another of my applications in MFC VC++ 6.0?
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Question by:JPM2002
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8 Comments
 
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Expert Comment

by:StefanKittel
ID: 24102394
Hello,

what do you mean? Please specify.

Stefan
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LVL 1

Expert Comment

by:DaRakNa
ID: 24102848
Command is:

You must replace "C:\\Cpp\\ExpertExchange\\2x.exe" with your second program exact location.
ShellExecute(NULL, NULL,"C:\\Cpp\\ExpertExchange\\2x.exe",NULL, NULL, SW_SHOWNORMAL);

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Expert Comment

by:DaRakNa
ID: 24102853
Also you must include dos.h library.
#include <dos.h>

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Expert Comment

by:DaRakNa
ID: 24102860
No need to include dos.h for this function.
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Author Comment

by:JPM2002
ID: 24103307
doesn't work.

Here is what I typed

HINSTANCE H;

H = ShellExecute(NULL, NULL, "C:\\Projects\\2PC\\Debug,NULL,NULL,SW_SHOWNORMAL");





I get 2 errors

error 2001: newline in constant    // I don't see any newlines

error 2143: syntax error: missing ')' before string  // don't see any parentheses missing
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LVL 1

Expert Comment

by:DaRakNa
ID: 24103313
Try this:
HINSTANCE H;
 
H = ShellExecute(NULL, NULL, "C:\\Projects\\2PC\\Debug.exe",NULL,NULL,SW_SHOWNORMAL);

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Author Comment

by:JPM2002
ID: 24103351
Not needed... I found that I had an extra quotation mark at the end before the closing parentheses
that was causing the errors.

Thanks it works great.


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Accepted Solution

by:
DaRakNa earned 1000 total points
ID: 24103407
Great. Don't forget to accept solution and asign points. :)
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