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How to convert multiple columns to rows in Oracle

I have a table that look like this

COL1      COL2      COL3

10      20      30
100      200      300

I want to reverse the colomns and rows, i.e., producing the following output
COL1      10      100
COL2      20      200
COL3      30      300

As there is no PIVOT function in oracle 91, i had to use DECODE
 SELECT DECODE(rn,1,'COL1',
                  2,'COL2',
                     3,'COL3') col_type,
         DECODE(rn,1,col1,
                    2,col2,
                     3,col3) VALUE
    FROM   t,
           (SELECT LEVEL rn
            FROM   dual
           CONNECT BY LEVEL <= 3) ;

It produces the following result
COL_TYPE      VALUE

COL1      10
COL1      100
COL2      20
COL2      200
COL3      30
COL3      300

How can I turn each column in the original table into each corresponding row and achieve the output as I mentioned in the beginning?

create table t (col1 integer, col2 integer, col3 integer);
insert into t values (10,20,30);
insert into t values (100,200,300);
select * from t;

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suecnus
Asked:
suecnus
  • 4
1 Solution
 
sdstuberCommented:
you can generate the columns dynamically by joining to user_tab_cols
SELECT   column_name, DECODE(n,
                             1,
                             col1,
                             2,
                             col2,
                             3,
                             col3)
                          VALUE
  FROM   t, (    SELECT   LEVEL n
                   FROM   DUAL
             CONNECT BY   LEVEL <= 3), user_tab_cols utc
 WHERE   table_name = 'T' AND column_id = n

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sdstuberCommented:
or you can just hardcode them, which you might as well do anyway since you have to hardcode them as part of the decode...
SELECT   DECODE(n,
                1,
                'COL1',
                2,
                'COL2',
                3,
                'COL3')
             col_type, DECODE(n,
                              1,
                              col1,
                              2,
                              col2,
                              3,
                              col3)
                           VALUE
  FROM   t, (    SELECT   LEVEL n
                   FROM   DUAL
             CONNECT BY   LEVEL <= 3)

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suecnusAuthor Commented:
Thanks for the answer, but isn't your Solution 2 (hardcoded columns) the same as the one I used in my question? It does not produce the desired output.
0
 
sdstuberCommented:
they both produce the same output, and that's because I was looking at your question wrong,  I was trying to duplicate the last results you posted (what you didn't want),
not the earlier ones which are what you wanted

sorry about that, that was my confusion
0
 
sdstuberCommented:
try this...

if you have more than 2 rows then simply add more of the MAX(DECODE....)) columns for each row you'll need to pivot.
You will need to know how many rows before hand though since SQL can't have dynamic columns.

If you need that you'll have to use pl/sql to generate a sql statement on the fly.
  SELECT   column_name col_type,
           MAX(DECODE(rn, 1, DECODE(n,
                                    1,col1,
                                    2,col2,
                                    3,col3))) x,
           MAX(DECODE(rn, 2, DECODE(n,
                                    1,col1,
                                    2,col2,
                                    3,col3))) y
    FROM   (  SELECT   col1, col2, col3, ROW_NUMBER() OVER (ORDER BY col1) rn FROM t),
           (    SELECT   LEVEL n
                  FROM   DUAL
            CONNECT BY   LEVEL <= 3),
           user_tab_cols utc
   WHERE   table_name = 'T' AND column_id = n
GROUP BY   column_name

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