FOR /F Tokens script to read first line only.

I'm currently using the line below in a batch script to find data in a text file.

for /f "tokens=3,4,5,6" %i in (myfile.txt) do @echo %i %j %k %l

The data (or columns) I want (3,4,5,6) are only from the 1st line of text in my input file myfile.txt.
My script will read the entire file and I'll end up with way more output than I need. I'd like to just scan the first line in my file for the data then exit. What do I need to do?

-thanks!
Bob
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ZabagaRAsked:
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Justin_W_ChandlerConnect With a Mentor Commented:
for /f "tokens=3,4,5,6" %i in (myfile.txt) do @echo %i %j %k %l >> %temp%\asdf.tmp
set /p var_FirstLine=<%temp%\asdf.tmp
echo %var_FirstLine%
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ZabagaRAuthor Commented:
Thank you.  The only correction I had to make was my own really, I have to put %%i (and for the other VARs too) in a batch script. Need double percent signs instead of single.
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Shift-3Commented:
You can add a GOTO command to skip to a label after it reads the first line.


for /f "tokens=3,4,5,6" %i in (myfile.txt) do (
 @echo %i %j %k %l
 goto :_next
)
 
:_next
REM rest of script here

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Justin_W_ChandlerCommented:
SHIFT-3 the other way is just to do this:

for /f "tokens=3,4,5,6" %i in (myfile.txt) do @echo %i %j %k %l & goto :eof
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ZabagaRAuthor Commented:
Thanks.  I appreciate it!!!
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