Remove the last zero character form a string

Hi;
I have a string field full of data like this" 18 10 6 4 1 0"
I mean that is the last character always space then zero "0"
I need function  to remove this zero  at all
please
Mohammad Alsolaimanapplication programmerAsked:
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rockiroadsConnect With a Mentor Commented:
sorry? fields you declare. Do you want vba

dim mynewstring as string

mynewstring = iif(right$(myfield,2) = " 0",left$(myfield,len(myfield)-2),myfield)

Otherwise Im not sure what you mean
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brandonvmooreConnect With a Mentor Commented:
Use the Left() and Len() functions:

select left(fieldname, len(fieldname) - 1)
or
select left(fieldname, len(fieldname) - 2)

Use "-1" if you want to leave the space on the end or "-2" if you want to get rid of the space and the 0.
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rockiroadsCommented:
what if you had something ending with 10, is that a possibility?
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rockiroadsCommented:
if always space then 0 then brandon's post will work for you. If not always space and 0 then try this

if last two chars is space and 0 then strip it off else leave as as

mystrippedfield: iif(right$(myfield,2) = " 0",left$(myfield,len(myfield)-2),myfield)

this can be put in your sql

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rockiroadsCommented:
is this stripping just for display purposes or do you want to update the data? what Ive posted is for select. If you want to update the data, it is like this

update mytable
set myfield = left$(myfield,len(myfield)-2)
where len(nz(myfield,""))>1 and right$(myfield,2) = " 0"

Need to actually take into account any fields that are null or have 1 char in them so added len(nz(myfield,""))>1
same would be needed in the select as well I guess


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Mohammad Alsolaimanapplication programmerAuthor Commented:
no i want some thing fore fields i declare, but not in sql statement
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Mohammad Alsolaimanapplication programmerAuthor Commented:
yes u r wright,
but there some thing else
i think the zero is in the first character,  and not as i mention before .
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rockiroadsCommented:
so it is zero and space
or space and zero

if zero and space

if len(myoldstring)>1 and left$(myoldstring,2) = "0 " then
    mynewstring = myoldstring
else
    mynewstring = myoldstring
end if

to replace myoldstring only

if len(myoldstring)>1 and left$(myoldstring,2) = "0 " then
    myoldstring = mid$(myoldstring,3)
end if


to replace space and zero, change "0 " to " 0"
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Mohammad Alsolaimanapplication programmerAuthor Commented:
wonderful
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Mohammad Alsolaimanapplication programmerAuthor Commented:
thanks a lot rocki
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rockiroadsCommented:
No probs
in case you got null strings, just add the check for the length
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Mohammad Alsolaimanapplication programmerAuthor Commented:
clear
thanks again
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