Solved

binary search algorithm on a circular list

Posted on 2009-04-14
9
909 Views
Last Modified: 2013-11-12
hi,

heard this was a google interview question and had need to use it myself.  

if i have a circular, sorted list of n values x(0),  x(1), x(2), ..... x(n-1) , and given a value u, what is the index that satisfies
x(i) <= u < x(i+1)

iterative searching seems wasteful.  i'd use a binary search on this, but how do you handle the circular nature of it?  what do you do at the crossovers?  are there any c++ algorithms out there that do this?  

what would YOU do?

lou
0
Comment
Question by:ugeb
9 Comments
 
LVL 37

Accepted Solution

by:
gregoryyoung earned 250 total points
ID: 24140785
if its in an array just do an offset binary search, its just a matter of adjusting the index appropriately for a binary search.

take a look at how to calculate the length of a circular in an array, it has pretty much everything you need to do offsetitng.


if its in say a linked list ... google (pun intended) what a skip list is ...
0
 
LVL 15

Assisted Solution

by:spprivate
spprivate earned 250 total points
ID: 24140819
There is an IEEE article on doing a circular binary search

http://ieeexplore.ieee.org/xpl/freeabs_all.jsp?arnumber=123386
0
 
LVL 11

Author Comment

by:ugeb
ID: 24140947
hey, thanx for those.


gregoryyoung: do you have any links to references?

spprivate:  i don't have an ieee account, is there a way to see article this without that?
0
 
LVL 37

Expert Comment

by:gregoryyoung
ID: 24141352
spprivate that article is not a simple binary search lol ... it looks like some link love from plugging keywords into a goodle search.

References? for which? is it an array or is it a linked list?

For an array do you really need one? its a simple arithmetic mapping to take the circular array and present it as 0-n. If you have a circular implementation just look at an index translation which is probably there already.

For a skip list http://en.wikipedia.org/wiki/Skip_list

Greg
0
Top 6 Sources for Identifying Threat Actor TTPs

Understanding your enemy is essential. These six sources will help you identify the most popular threat actor tactics, techniques, and procedures (TTPs).

 
LVL 11

Author Comment

by:ugeb
ID: 24142109
hi,

it's a list, but not a linked list ... i.e. an array, but a circular and sorted array.

without having to get as complicated as a skip list, how would you do a simple binary search on this and then handle the problem of not knowing where the end points are?

let's say the list (array) is
{ 7,8,9,10,11,12,1,2,3,4,5,6}

now i want to find out where 3 belongs.  if i split the array in half, half 1 will be sorted, but half 2 will contain a jump.  is there an efficient way to handle that?






0
 
LVL 3

Expert Comment

by:sprjp2
ID: 24143269
When you split the array, at least one half is sorted. You can find out which one by comparing its first and last element. In this way you can find the offset by which the array was shifted.
0
 
LVL 11

Author Closing Comment

by:ugeb
ID: 31570052
I was really hoping for more ideas and direction. Thanks.
0
 
LVL 37

Expert Comment

by:gregoryyoung
ID: 24160350
9 0 1 2 3      4 5 6 7 8
head = 1
tail = 0

3 4 5 6 7      8 9 0 1 2

head = 7
tail = 6


head and tail are both on the same side ... that side is offset

0 1 2 3 4     5 6 7 8 9
head = 0
tail = 9

both sides are sorted


If you later end up with neither head or tail in your segment you know that it is sorted continue as a normal binary search.


We know that we can do a normal binary search if we are on the sorted side. If we are not on the sorted side then we have to realize where our offset is

head->length = sorted
tail->start = sorted


From here we can keep with a binary search and just take the head/tail as a split point to figure out which one to search

we know that

start -> tail is sorted
and that head->length is sorted

so do some quick checks to see which of those ranges we fall into pick the one that we fall into and do a normal binary search ... If you only have one then pick that range (the rest is space you don't care about)



Hope this helps you in terms of more detail, I saw you commented on the question that you wanted more.

Greg
0
 
LVL 11

Author Comment

by:ugeb
ID: 24175936
hey,

thanks for the additional comment.  that's what I ended up doing, so i'm glad to know i was on the right track.

thanks again.
0

Featured Post

Threat Intelligence Starter Resources

Integrating threat intelligence can be challenging, and not all companies are ready. These resources can help you build awareness and prepare for defense.

Join & Write a Comment

Suggested Solutions

Iteration: Iteration is repetition of a process. A student who goes to school repeats the process of going to school everyday until graduation. We go to grocery store at least once or twice a month to buy products. We repeat this process every mont…
Exception Handling is in the core of any application that is able to dignify its name. In this article, I'll guide you through the process of writing a DRY (Don't Repeat Yourself) Exception Handling mechanism, using Aspect Oriented Programming.
It is a freely distributed piece of software for such tasks as photo retouching, image composition and image authoring. It works on many operating systems, in many languages.
In this seventh video of the Xpdf series, we discuss and demonstrate the PDFfonts utility, which lists all the fonts used in a PDF file. It does this via a command line interface, making it suitable for use in programs, scripts, batch files — any pl…

746 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

17 Experts available now in Live!

Get 1:1 Help Now