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Help with my perl script

Posted on 2009-04-14
21
Medium Priority
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Last Modified: 2012-05-06
hello, I have this script but it fails to run. It was orginaly set to run on a unix box( See below), so I changed the path to my my windows path wihere my input file is located.

When I run it, it fails to look at my directory where the files are located.

My input file is located at c:\named.conf-rich

Can someone fix this so it will run on my windows box.

Thanks

#!/perl
 
unless ($ARGV[0])  {
    print "******************************************************\n";
    print "*                                                    *\n";
    print "*                                                    *\n";
    print "******************************************************\n";
    exit;
}
 
$inputfile=$ARGV[0];
$zonefound = 0;
 
open(INFILE, $inputfile) or die "Unable to find $inputfile\n";
@conf = <INFILE>;
close INFILE;
 
foreach $linein (@conf)  {
    chomp($linein);
    $count++;
 
        if ($linein =~ /^zone\s+\".*in-addr.arpa\"/)  {
            $countZONE++;
            $zonefound = 1;
            ($j1, $j2, $j3, $j4, $j5) = split " ",$linein;
#print "ZONE-START: $linein\n";
        }
        elsif (($zonefound == 1) and ($linein =~ /^\}/))  {
            $zonefound = 0;
#print "  ZONE-END: $linein\n";
        }
        elsif (($zonefound == 1) and ($linein =~ /allow-update/))  {
print "$j2,$linein\n";
        }
        else {
                next;
        };
 
};

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Question by:richsark
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21 Comments
 
LVL 84

Expert Comment

by:ozo
ID: 24141885
Do you get an error when you run it?
0
 
LVL 1

Author Comment

by:richsark
ID: 24142031

Hi,
Well, first I am unsure of the $input file in terms of what I need to set. I do know that my input file is located in c:\named.conf\-rich

In that directory I have tons of file called
named.conf.6cmghnsrt01.netdevice.rich.com

What this script will do is look at the contents of what is directed.

So, I want to make sure when I run this script, I need it to look at the directory c:\named.conf\-rich and look at all the files that begin with named.conf and pull out what the script does.

I think the script runs with script name and filename, checkconf.pl

named.conf.6cmghnsrt01.netdevice.rich.com
 
I do not want it to do that. I want it to look in my dir and do it automaticlay.
Thanks
0
 
LVL 84

Expert Comment

by:ozo
ID: 24142113
do you want to read @ARGV=<c:/named.conf/-rich/*>?
how would you have done what you are trying to do in unix?
the code snippet does not seem to match your description.
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LVL 1

Author Comment

by:richsark
ID: 24142221
Hi, yes, My script for unix is what I want to make work for my needs. The script I have is a baseline which I think is close to what I need.
So, yes my input file is c:\named.conf-rich which will contain all the files I need for this script to read.
Thanks Ozo
0
 
LVL 1

Author Comment

by:richsark
ID: 24142766
hi, does that help?
0
 
LVL 39

Expert Comment

by:Adam314
ID: 24143146
The script you posted expects you to give it the name of a file as a command line argument, like so:
    script.pl c:\named.conf-rich\list.txt

The script then reads that file, and counts the number of zones (lines beginning with "zone") in them.  
0
 
LVL 1

Author Comment

by:richsark
ID: 24143175
Hi Adam, I know , I want it to read a specific directory and work from there. That is why I needed this script to be slightly re-worked.
I rather have this script work in a wau where I excute the script, it will look in my directory, in this case c:\named.conf-rich
In there it will find all the files that start with named.conf.xxxxx and spit out what its designed to do from there.
Does that sound do'able
0
 
LVL 84

Expert Comment

by:ozo
ID: 24143225
#open(INFILE, $inputfile) or die "Unable to find $inputfile\n";
#@conf = <INFILE>;
#close INFILE;
 
#foreach $linein (@conf)  {

@ARGV=<$inputfile/named.conf.*>;
while( $linein=<> ){

0
 
LVL 1

Author Comment

by:richsark
ID: 24143265
Hi Ozo, so this will go like this in my scirpt
#!/perl
 
unless ($ARGV[0])  {
    print "******************************************************\n";
    print "*                                                    *\n";
    print "*                                                    *\n";
    print "******************************************************\n";
    exit;
}
 
#open(c:\named.conf-rich, $inputfile) or die "Unable to find $inputfile\n";
#@conf = <INFILE>;
#close INFILE;
 
#foreach $linein (@conf)  {
 
@ARGV=<$c:/named.conf-rich/named.conf.*>;
while( $linein=<> ){ 
foreach $linein (@conf)  {
    chomp($linein);
    $count++;
 
        if ($linein =~ /^zone\s+\".*in-addr.arpa\"/)  {
            $countZONE++;
            $zonefound = 1;
            ($j1, $j2, $j3, $j4, $j5) = split " ",$linein;
#print "ZONE-START: $linein\n";
        }
        elsif (($zonefound == 1) and ($linein =~ /^\}/))  {
            $zonefound = 0;
#print "  ZONE-END: $linein\n";
        }
        elsif (($zonefound == 1) and ($linein =~ /allow-update/))  {
print "$j2,$linein\n";
        }
        else {
                next;
        };
 
};

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LVL 84

Expert Comment

by:ozo
ID: 24143304
no,
#foreach $linein (@conf)  {
should be  commented out
and $c would need to be defined.
If you are not reading $c = $ARGV[0];
instead of $inputfile=$ARGV[0];
then you could code the path you want into the <>
0
 
LVL 1

Author Comment

by:richsark
ID: 24143326
Hi Ozo, can you please put the final code below so there is not to much back and forth.
I appericate it Ozo/Adam
Thanks
0
 
LVL 84

Assisted Solution

by:ozo
ozo earned 920 total points
ID: 24143373
#!/perl
 
#unless ($ARGV[0])  {
#    print "******************************************************\n";
#    print "*                                                    *\n";
#    print "*                                                    *\n";
#    print "******************************************************\n";
#    exit;
#}
 
#$inputfile=$ARGV[0];
$zonefound = 0;
 
#open(INFILE, $inputfile) or die "Unable to find $inputfile\n";
#@conf = <INFILE>;
#close INFILE;
 
#foreach $linein (@conf)  {

@ARGV=<c:/named.conf-rich/named.conf.*>;  #it looks like you want to ignore $inputfile=$ARGV[0];
 and always look for c:/named.conf-rich/named.conf.*
while( $linein=<> ){

    chomp($linein);
    $count++;
 
        if ($linein =~ /^zone\s+\".*in-addr.arpa\"/)  {
            $countZONE++;
            $zonefound = 1;
            ($j1, $j2, $j3, $j4, $j5) = split " ",$linein;
#print "ZONE-START: $linein\n";
        }
        elsif (($zonefound == 1) and ($linein =~ /^\}/))  {
            $zonefound = 0;
#print "  ZONE-END: $linein\n";
        }
        elsif (($zonefound == 1) and ($linein =~ /allow-update/))  {
print "$j2,$linein\n";
        }
        else {
                next;
        };
 
};
0
 
LVL 1

Author Comment

by:richsark
ID: 24143412
Awsome, so where it says
#@conf = <INFILE>;
I need to put:
@conf = <c:\named.conf-rich>;
0
 
LVL 39

Expert Comment

by:Adam314
ID: 24143436
In the new code, @conf isn't used.  This line:
    @ARGV=<c:/named.conf-rich/named.conf.*>;
is the line that searches for the files named c:\named.conf-rich\named.conf.*.

Then this line:
    while( $linein=<> ){
is what reads from those files, one line at a time.
0
 
LVL 84

Expert Comment

by:ozo
ID: 24143452
No, that's not what I wrote.
But now I'm getting confused
But is c:\named.conf-rich a text file or a directory
0
 
LVL 1

Author Comment

by:richsark
ID: 24143489
ok, so we can assume this puppy will work as below
#!/perl
 
#unless ($ARGV[0])  {
#    print "******************************************************\n";
#    print "*                                                    *\n";
#    print "*                                                    *\n";
#    print "******************************************************\n";
#    exit;
#}
 
#$inputfile=$ARGV[0];
$zonefound = 0;
 
#open(INFILE, $inputfile) or die "Unable to find $inputfile\n";
#@conf = <INFILE>;
#close INFILE;
 
#foreach $linein (@conf)  {
 
@ARGV=<c:/named.conf-rich/named.conf.*>;  #i ignore $inputfile=$ARGV[0];
 and always look for c:/named.conf-rich/named.conf.*
while( $linein=<> ){
 
    chomp($linein);
    $count++;
 
        if ($linein =~ /^zone\s+\".*in-addr.arpa\"/)  {
            $countZONE++;
            $zonefound = 1;
            ($j1, $j2, $j3, $j4, $j5) = split " ",$linein;
#print "ZONE-START: $linein\n";
        }
        elsif (($zonefound == 1) and ($linein =~ /^\}/))  {
            $zonefound = 0;
#print "  ZONE-END: $linein\n";
        }
        elsif (($zonefound == 1) and ($linein =~ /allow-update/))  {
print "$j2,$linein\n";
        }
        else {
                next;
        };
 
};

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LVL 39

Accepted Solution

by:
Adam314 earned 1000 total points
ID: 24143538
Cleaning up your code...
#!/perl
 
$zonefound = 0;
@ARGV=<c:/named.conf-rich/named.conf.*>;
 
while( $linein=<> ){
    chomp($linein);
    $count++;
    if ($linein =~ /^zone\s+\".*in-addr.arpa\"/)  {
        $countZONE++;
        $zonefound = 1;
        ($j1, $j2, $j3, $j4, $j5) = split " ",$linein;
    }
    elsif (($zonefound == 1) and ($linein =~ /^\}/))  {
        $zonefound = 0;
    }
    elsif (($zonefound == 1) and ($linein =~ /allow-update/))  {
        print "$j2,$linein\n";
    }
    else {
        next;
    }
}

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0
 
LVL 1

Author Comment

by:richsark
ID: 24143617
Ok, will get back when a few
0
 
LVL 84

Expert Comment

by:ozo
ID: 24143635
#If I'm understanding what you are doing, it looks like your entire program may be

@ARGV=<c:/named.conf-rich/named.conf.*>;
(($j2)=/^zone\s+(".*in-addr.arpa")/) .. /^}/ and /allow-update/ and print "$j2,$_"  while <>;

0
 
LVL 5

Assisted Solution

by:vikaskhoria
vikaskhoria earned 80 total points
ID: 24145462
I guess the basic problem you were facing initially is like this:
When you were using arguments for giving the path, then you were entering the path with front slashes '\'
Whereas for perl script you should have done it with '/'

So the argument should have been 'c:/named.conf-rich' instead of 'c:\named.conf-rich'.
Rest of the logic changes for reading all files in the directory is well suggested by experts above.
I just added this, in case you again want to take user input for path, instead of hard coding.
0
 
LVL 1

Author Closing Comment

by:richsark
ID: 31570115
Excellent work !
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