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vb.net 2008 select query in datatable and display in datagridview

Posted on 2009-04-14
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Last Modified: 2013-11-26
I already have datatable fill with data.
i need code in vb.net 2008 to do select query in datatable and display in datagridview.
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Question by:aarontham
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7 Comments
 
LVL 12

Expert Comment

by:wht1986
ID: 24144639
I only have c# installed here but it should be easy to port from:

 DataSet1 ds = new DataSet1();
 BindingSource bindSource = new BindingSource();
 bindSource.DataSource = ds;
 bindSource.DataMember = "DataTable1";
 this.dataGridView1.DataSource = bindSource;
0
 
LVL 12

Expert Comment

by:wht1986
ID: 24144646
sorry forgot to add you can use filter for the same effect as doing a select.

bindSource.Filter = "MyColumnName > 5";
0
 
LVL 53

Expert Comment

by:Dhaest
ID: 24145082
You can also perform a linq-query to get your result from the datatable into your datagridview.

Example:
Dim Query = From i In YourDataTable.AsEnumerable() _
         Where i.Field(Of String)("YourField") = "Status"

DataGridView_Customer.DataSource = Query.AsDataView()

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Author Comment

by:aarontham
ID: 24145165
hi Dhaest:

i don't understand on the Query part. below is my code help to modify to use your code.

Public rsName As New DataTable
Dim custRows() As DataRow = rsName.Select("CusName like  '%" & (TextBox38.Text) & "%'")
0
 
LVL 53

Expert Comment

by:Dhaest
ID: 24145209
Dim Query = From i In rsName.AsEnumerable() _
         Where SqlMethods.Like(i.CusName, "%" & TextBox38.Text & "%")
0
 

Author Comment

by:aarontham
ID: 24145284
hi Dhaest,

Do work. have error on SqlMethods

it say SqlMethods not declare and Where not declare.
0
 
LVL 53

Accepted Solution

by:
Dhaest earned 500 total points
ID: 24145338
Imports System.Linq
Imports System.Data.Linq.SqlClient

        Dim TextBox38 As TextBox = New TextBox
        TextBox38.Text = ""

        Dim rsName As New DataTable
        rsName.Columns.Add(New DataColumn("CusName"))
        Dim Query = From i In rsName.AsEnumerable() _
         Where SqlMethods.Like(i("CusName"), "%" & TextBox38.Text & "%")
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