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Date Diff Issue in Excel VB

Posted on 2009-04-14
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Last Modified: 2012-08-13
I think I have dates finally figured out and then the whole date diff thing is throwing me for a loop. I have a column (AW) of dates. What I want to do is determine if the date in the column is greater than 4 years in the past (in this case I'm using days so that if it's greater than 1460 days) then to enter the number 1 44 columns to the right of the date in the cell. My dates are formatted in column AW as MM-DD-YYYY. I expect I'm having a problem with not seting a date specificaion type but unsure really how to do it. I've complicated my code so much that I don't even know what's right anymore and unsure if a case is better to use than a nested if then.
I think if someone can just help me figure out the syntax of
If DateDiff("d" date1,date2 ) > 1460 then
cell.Offset(0, 44) = 1

where date 1 is the date value in a cell in column AW Thanks
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Question by:luminent
7 Comments
 
LVL 12

Expert Comment

by:Alan3285
ID: 24144686
This will compare B2 and C2 (with C2 being the 'anchor' cell) and put a 1 across 44 cols from C2.

Alan.

 
Sub Test()
 
Set MyCell = Range("C2")
 
    If DateDiff("d", MyCell.Offset(0, -1).Value, MyCell) > 1460 Then
    
        MyCell.Offset(0, 44).Value = 1
 
    End If
 
End Sub

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Expert Comment

by:RiteshShah
ID: 24144699
don't understand by "What I want to do is determine if the date in the column is greater than 4 years in the past"????

you enter first date in AW column than where is second data?

Please elaborate your question bit more.
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LVL 6

Expert Comment

by:BALMUKUND KESHAV
ID: 24144843
Your question is not clear :
if you want to compare a cell having date value with particular date and want to put any spcific value in specific col. then use this :
if(b1-c1>1460,"put your true value","else false value")
put the above command in cell where you want the result.

Regards,

Bm Keshav

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LVL 59

Expert Comment

by:Chris Bottomley
ID: 24145081
If you are concerned at text form dates then forcing them to dates may help:

If DateDiff("d" cdate(date1),cdate(date2)) > 1460 then
cell.Offset(0, 44) = 1

Chris
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LVL 9

Accepted Solution

by:
felixdsouza earned 250 total points
ID: 24145178
Try out this..
Sub Test()
    Dim DtToday As Date
    Dim Dt As Date
    
    Dim FirstRow As Long
    Dim LastRow As Long
    Dim CurrentRow As Long
    
    Dim CurrentCol As Integer
    FirstRow = 1
    LastRow = [AW65536].End(xlUp).Row
    
    DtToday = Int(Now)
    CurrentCol = [AW1].Column
    For CurrentRow = FirstRow To LastRow
        Cells(CurrentRow, CurrentCol).Select
        Dt = Cells(CurrentRow, CurrentCol)
        If DateDiff("d", Dt, DtToday) > 1460 Then
            Cells(CurrentRow, CurrentCol).Offset(0, 44) = 1
        End If
    Next CurrentRow
End Sub

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Author Closing Comment

by:luminent
ID: 31570438
Thanks so much for understanding what I was asking. Not only did I learn how to actually include a better way of using a cell value for a date compare (which I've incorporated into a few other subroutineson the same project) but also a different way of moving through rows in a column than I had been doing. It's these little pieces of wisdom that you gather that really help in bridging the gaps between what books teach and the practical applications.
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LVL 9

Expert Comment

by:felixdsouza
ID: 24154397
By the way, the line

Cells(CurrentRow, CurrentCol).Select

is not required.  I had inserted it for debugging purpose and forgot to remove it before posting the solution.  If you need to run the macro on a large number of rows of data, removing this line will speed up execution to a great extent.
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