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How to determine size limits on Distribution Groups Outlook 2007

Microsoft distro lists seem to have a size limit on them that is very frustrating when trying to build larger lists. Typically we can only get about 70~80 users in a list and, while I have got a workaround, I'd like to know if there is some way to determine the size or if the distro list size can be expanded?
Thanks to all for any comments, suggestions, etc.
Kd
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kevindubay
Asked:
kevindubay
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2 Solutions
 
Rajith EnchiparambilOffice 365 & Exchange ArchitectCommented:
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kevindubayAuthor Commented:
Thank you ...already found that solution....I appreciate the reply...

I will close this question
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Rajith EnchiparambilOffice 365 & Exchange ArchitectCommented:
I have given kevin the answer as soon as he posted the question. Now, after couple of hours, he comes back and says that he has found the same answer.

I don't understand why these people post questions here, if they don't want to look at the answers the experts post!
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kevindubayAuthor Commented:
Well...I guess the thing is that I can do research just as easily as you can...if your such an expert WHY just post a plain ol' link to a microsoft support page.....?!?!  I'm looking for EXPERT advice...if I wanted someone to tell me to go look at a link I could have gotten that from Google.  I pay a regular monthly subscription for this service and I can do the same thing you did EXCEPT I don't consider myself an expert for giving out links. Sorry if this sounds a little condescending but its the first time I've ever posted a question on this site and I've had the subscription for roughly a year now.  
I think this service can be AND IS a good service I just don't think its fair to you (or me) to continue on with a thread that is going to get pretty much the same answer to my question no matter where I search. I apologize for the posting
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Rajith EnchiparambilOffice 365 & Exchange ArchitectCommented:
The problem you had is a well known one and well documented by Microsoft. You failed to pick it up in your search (if you did) and hence posted your question here.

As it is fully explained and documented, I pointed you to the link. There is no point in me explaining the same in my own words when an MS document is out there covering it. So, are you saing that you can't even read the doc explaining the solution?

You need to understand that people who try to help are not paid by the site. There are spending their own time to help and you fail to respect that.
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kevindubayAuthor Commented:
Ok...I apologized for the posting and now you're giving me a hard time because you think I can't do my own research and find some things on my own?!?!  And you insult me by insinuating that I don't/can't read?!?!  Here's the thing...I did fail to mention that I found the same solution you posted, and I apologized for that and I also failed to mention that I read that MS support post but I did and it wasn't the answer I was looking for...so thats a crime in this forum...?!?!   I guess I'm just trying to understand WHY you are upset with the fact that I replied with an answer that I had already found your suggestion??  Or, is the fact that I tried to close the question?  What is it that you get out of this?? are you pi$$ed that you don't get POINTS for helping someone??  I see that this forum is based on some point system, which I do not  or have not READ about nor do I care that much about. I use this forum to get EXPERT advice AND YES get pointed to relevent material / information on the web that will help me solve a problem. So again, I apologize if you don't get anything for helping but I thanked you for your reply and informed you that I had already found that solution and again I will apologize for your inconvenience but if you care nothing about HELPING someone and just want to start a flame war about whether I stomped on your sensibilites then I guess I should probably withdraw my monthly subscription to this site and go find somewhere else to get EXPERT advice.
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kevindubayAuthor Commented:
sorry for the misunderstanding with how this forum works. I'm giving maximum points for Rajith's answer...thanks
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