Can i create a dictionary in python that uses ranges?

Your keys are 1, 4 and 9. "1-3" and "4-8" is constructed by looking at the next key: 3 = 4-1, and 8=9-1. But where does 12 come from?

This is just an example, so i just choose 12 at random. Is it important to look at the next key?

Thanks

>> Is it important to look at the next key?

Depends. What do you mean by ranges? I am just guessing what you want based on your example.

Is this what you want:

dict([('1-3', 'abc'), ('4-8', 'def'), ('9-12', 'ghi')])

Yes, is that how you implement it in Python?

Or maybe this:

d = dict([(1, 'abc'), (4, 'def'), (9, 'ghi')])
for i in range(len(d.keys())):
    print "%d-%-2d -- %s"%(L[i],L[i+1]-1 if i<len(d.keys())-1 else 12,d[L[i]])

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>> is that how you implement it in Python?

Implement what? This is a hardcoded dictionary:

dict([('1-3', 'abc'), ('4-8', 'def'), ('9-12', 'ghi')])

The dict() function returns a dictionary. It is the same as this:

{'1-3': 'abc', '4-8': 'def',  '9-12': 'ghi'}

The code in my last code snippet is an algorithm, it can be used with different dictionaries as input.

If you describe your requirement in more detail, it would be easier to help you. :)

Sorry, i've just realised i've not been very clear. Say i have this dictionary:


1-3   -- abc
4-8   -- def
9-12 -- ghi

if i then entered:

dictname [2];

for example it would reurn abc, and if i entered dictname[7] it would return def

ok, i'll do some experiments and report back.

thanks

Thank you, this is what i wanted.