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Andreas HermleFlag for Germany

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RGB value of selected shaded cell

Dear Experts:

I would like to retrieve the RGB value of the selected shaded cell of a word table and display it in a msgbox.
Help is much appreciated. Thank you very much in advance. Regards, Andreas
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Chris Bottomley
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Hello AndreasHermle,

SOmething like the following perhaps:

Regards,
Chris
Sub cellRGB()
Dim str As String 
str = "Color is :" & vbCrLf & vbCrLf
With Application.ActiveCell.Interior
    str = str & "Red:   " & CStr(&HFF& And .Color) & vbCrLf
    str = str & "Green: " & CStr((&HFF00& And .Color) \ 256) & vbCrLf
    str = str & "Blue:  " & CStr(.Color \ 65536) & vbCrLf
End With
MsgBox str, vbOKOnly, "Cell Interior RGB" 
End Sub

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SOLUTION
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GrahamSkan
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Keeping the structure from Grahams solution and merging it with the RGB display produces for example the following:

Chris
Function RGBValue(rng As Range) As String
    Dim cl As Word.Cell
    Dim RGBValueF As Long
    Dim RGBValueB As Long
    Set cl = rng.Cells(1)
    RGBValueF = cl.Shading.ForegroundPatternColor
    RGBValueB = cl.Shading.BackgroundPatternColor
    RGBValue = "Foreground; " & RGB(RGBValueF) & vbCrLf & "Background; " & RGB(RGBValueB)
End Function
 
Function RGB(lng As Long) As String
    lng = Abs(lng)
    RGB = "Color is :" & vbCrLf & vbCrLf
    RGB = RGB & "Red:   " & CStr(&HFF& And lng) & vbCrLf
    RGB = RGB & "Green: " & CStr((&HFF00& And lng) \ 256) & vbCrLf
    RGB = RGB & "Blue:  " & CStr(lng \ 65536) & vbCrLf
End Function

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Avatar of Andreas Hermle

ASKER

Dear Graham and Chris,

thank you very much for your swift help. I do not know how to call up this function. I guess I need to call it from an existing macro. If the latter is true, this macro should be just a stand-alone macro with no more code.
How would you like to call it? ... for example run via the tools macro run menu using the activecell?

Chris
Other options are to attach the macro to a new button on a toolbar and/or to create a keystroke shortcut. These are both done via the Customise dialogue.
Dear Chris and Graham,
I guess you did not understand me correctly. Am I right, but this function must be 'embedded' in a macro starting with Sub someName() and End Sub? If running this macro (the cursor resides in some selected cell of some table) a msgbox should come up, telling me which RGB value the selected cell has.

I hope I could make myself clear.

Regards, Andreas
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Dear Chris,
that's it. Thank you very much for your professional help. I am not quite sure about how to distribute the points. Graham also contributed to the solution, at least at the beginning. Would it be ok to do a 350 to 150 split or 400 to 100 with you getting the bigger share?

Regards, Andreas  
Absolutely right that Graham should get a share so whichever split you like ...

But hes a genius and i'm a mere master so perhaps 499 to me and 1 to him ;o) nah joshing aside I would say 350 : 150 is the fairer of the options you proposed.

Chris
Again, thank you for your professional help. Regards, Andreas