Still celebrating National IT Professionals Day with 3 months of free Premium Membership. Use Code ITDAY17

x
Solved

# How to get regular expresson ti limirt number of digits to be entered by user

Posted on 2009-05-04
Medium Priority
404 Views
This would seem very simple because I only want my user to be able to enter up to 2 digits followed by a . char followed by up to 2 decimal places.

So in other words a floating point value such as 99.99 or 3.45 or 37.8 but not 888 or 888.88.

Now my Javascript regular expression to allow up to 2 digits before the floating point looks like this:

var regExp = /[0-9]{1,2}/

but what I don't understand is that this expression returns true when I call
regExp.test("888"); ?????

Can anyone explain this and tell me what I should be putting to ensure the 3rd digit causes an invalid result?

Many thanks
Sam

0
Question by:Samm1502
[X]
###### Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

• Help others & share knowledge
• Earn cash & points

LVL 84

Accepted Solution

ozo earned 1000 total points
ID: 24293552
/[0-9]{1,2}/ can match either the first 88 or the last 88 in "888"
/^[0-9]{1,2}\./
would only allow . and not 8 after the first 88
0

LVL 9

Expert Comment

ID: 24293750
yes its actually quite simple that you don't need a regular expression for that.  so according to this

>> So in other words a floating point value such as 99.99 or 3.45 or 37.8 but not 888 or 888.88.

you can
1) check whether the string has a decimal "." .
2) if there's decimal
a) split the string on "." as delimiter.
b) check 1st element and 2nd element whether they less than 99 and more than 0.

0

Author Comment

ID: 24295105
Thanks ghostdog74 but I have to use a regular expressions for reasons I won't bore you with and ozo if I read this correctly it test for the existence of any char not in the range [0-9] but I need to make sure my regexp.test call returns true if the entered value is valid and false otherwise so how do I alter my original expression to prevent it matching part of the entered string and force it match all of it i.e. allwo just 1 or 2 digits before the . and 1 or 2 digits afterwards?

Many thanks.
Sam
0

LVL 35

Assisted Solution

Terry Woods earned 1000 total points
ID: 24299178
In ozo's solution
/^[0-9]{1,2}\./
the ^ matches the start of the string.

Altering it to restrict it to 1 or 2 digits after the decimal would be:
/^[0-9]{1,2}\.[0-9]{1,2}\$/

\$ matches the end of the string.
0

Author Closing Comment

ID: 31577483
Thanks for the explanation. Cheers Sam
0

## Featured Post

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

I have been reconstructing a PHP-based application that has grown into a full blown interface system over the last ten years by a developer that has now gone into business for himself building websites. I am not incredibly fond of writing PHP code o…
Do you hate spam? I do, and I am willing to bet you do as well. I often wonder, though, "if people hate spam so much, why do they still post their email addresses on the web?" I'm not talking about a plain-text posting here. I am referring to the fa…
Learn how to match and substitute tagged data using PHP regular expressions. Demonstrated on Windows 7, but also applies to other operating systems. Demonstrated technique applies to PHP (all versions) and Firefox, but very similar techniques will w…
Explain concepts important to validation of email addresses with regular expressions. Applies to most languages/tools that uses regular expressions. Consider email address RFCs: Look at HTML5 form input element (with type=email) regex pattern: T…
###### Suggested Courses
Course of the Month9 days, 22 hours left to enroll