the code works when there are id's linewise means1,2,3,4 otherwise it gives error,please help me out.

<form name="form" action="2.php" method="post">
<input type="submit" name="submit" id="submit" value="save" /><br />
 
<?php
$con=odbc_connect('try','','');
 
$sql="select * from tablename1 order by id";
$query=odbc_exec($con, $sql);
while (odbc_fetch_row($query))
{	//echo "t".$query['id'];exit;
	echo $id="t".odbc_result($query,"id");
	//exit;
	?>
		<input type="text" name="<?php echo "t".odbc_result($query,"id"); ?>" />
		<a href="2.php?id=<?php echo $id=odbc_result($query,"id"); ?>"><?php echo $name=odbc_result($query,"name"); ?></a>
	<br /><br />
	<?php
}
 
	if(isset($_POST['submit'])){
		  for($i=1;$i<count($_POST);$i++){
		  	//echo $_POST["t".$i]."<br>";
			$con=odbc_connect('try','','');
			$sql_command = "select name from tablename1 where id=$i";
			$rs_person = odbc_exec($con, $sql_command);
			$person = odbc_fetch_row($rs_person);
			$c[$_POST["t".$i]]= odbc_result($rs_person,"name");
			//$c[$_POST["t".$i]]=$person['name'];
		  }
		  
		  
		  for($i=1;$i<count($_POST);$i++){
				echo $c[$i]."<br>";		// echo in this fashion $a[1], $a[2] and so on in the order wise
		  }
		  
		  //echo count($_POST)-1;exit;
		  for($i=1;$i<count($_POST);$i++){
		  		//echo $i."<br>";
				//echo $_POST["t".$i]."<br>";
				$con=odbc_connect('try','','');
				$sql_command1 = "update tablename1 set `order1`=". $_POST["t".$i]." where id=$i";
				$ok=odbc_exec($con, $sql_command1);
				//echo "<br><br>";
				echo "<br>";
		  }
	}
?>
</form>

Select allOpen in new window