Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people, just like you, are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
Solved

Object Variable or With Block Variable Not Set Error

Posted on 2009-05-05
4
857 Views
Last Modified: 2013-11-28
I  will appreciate if I could get an assistance in resolving the error below.

Run-Time Error "91" error
"Object Variable or With Block Variable Not Set not set"
Public Sub DeleteRenumber()
 
    Dim rs As DAO.Recordset
    Dim cbo As String
    Dim i As Integer
    Dim bLoop As Boolean
    Dim sPrefix As String
    Dim sSql As String
 
On Error GoTo Err_cmdDelete_Click
 
    bLoop = True
     
    sPrefix = "XW-" & rs!TestType & "-" & rs!CTypeID & "-" & rs!BNo & "-" & rs!LNo & "-" & rs!STypeID & "-"
    'Find next number from one about to be deleted
    i = Val(Mid$(Me.FDID, 2)) + 1
      
    'Now update existing records
    Set rs = Me.RecordsetClone
 
    'Find first next highest number
    sSql = "FDID = '" & sPrefix & Format(i, "00") & "'"
    Debug.Print "Looking for", sSql
    rs.FindFirst sSql
    Do While bLoop
 
        'If no records found, end loop
        If rs.NoMatch = True Then
            bLoop = False
        Else
 
            'Decrement number
            Debug.Print "Updating ID", rs!SID
            
            rs.Edit
            rs!FDID = sPrefix & Format(i - 1, "00")
            rs.Update
 
            'Find next highest
            i = i + 1
            sSql = "FDID = '" & sPrefix & Format(i, "00") & "'"
            Debug.Print "Finding next", sSql
            rs.FindNext "FDID = '" & sPrefix & Format(i, "00") & "'"
        End If
    Loop
 
    'Closedown
    rs.Close
    Set rs = Nothing
 
    Me.Requery
    
Exit_cmdDelete_Click:
    Exit Sub
 
Err_cmdDelete_Click:
    MsgBox Err.Description
    Resume Exit_cmdDelete_Click
 
End Sub

Open in new window

0
Comment
Question by:billcute
  • 2
4 Comments
 
LVL 84
ID: 24303272
Can you determine the line where this occurs? Set a breakpoint at the beginning of the code, then run it and "walk" through it to find the offending line.

However, typically you should check for a NoMatch or .EOF when using FindFirst. If your code doesn't find anything, the rs variable would not be "set", and you would get this error:

rs.FindFirst sSql

If rs.NoMatch Then
  Msgbox "No Record Found"
  Exit Sub
Else
    Do While bLoop
    etc etc etc
End If
0
 
LVL 84
ID: 24303278
Sorry, just saw where you ARE using NoMatch ... not sure how that one slipped past.

So, again: Can you determine the offending line?
0
 
LVL 65

Accepted Solution

by:
rockiroads earned 500 total points
ID: 24303457
It may be down to the usage of rs! before it has been initialised

You got this line

    sPrefix = "XW-" & rs!TestType & "-" & rs!CTypeID & "-" & rs!BNo & "-" & rs!LNo & "-" & rs!STypeID & "-"


then you got

    Set rs = Me.RecordsetClone


Should be the other way round.
0
 
LVL 4

Author Comment

by:billcute
ID: 24307742
sorry...LSMConsulting

rockiroads suggestion resolved the error
0

Featured Post

Free Tool: ZipGrep

ZipGrep is a utility that can list and search zip (.war, .ear, .jar, etc) archives for text patterns, without the need to extract the archive's contents.

One of a set of tools we're offering as a way to say thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

This article is a continuation or rather an extension from Cascading Combos (http://www.experts-exchange.com/A_5949.html) and builds on examples developed in detail there. It should be understandable alone, but I recommend reading the previous artic…
Regardless of which version on MS Access you are using, one of the harder data-entry forms to create is one where most data from previous entries needs to be appended to new records, especially when there are numerous fields and records involved.  W…
Basics of query design. Shows you how to construct a simple query by adding tables, perform joins, defining output columns, perform sorting, and apply criteria.
With Microsoft Access, learn how to specify relationships between tables and set various options on the relationship. Add the tables: Create the relationship: Decide if you’re going to set referential integrity: Decide if you want cascade upda…

809 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question