?
Solved

Building sql select statement for results page using PHP

Posted on 2009-05-05
2
Medium Priority
?
301 Views
Last Modified: 2013-12-12
I'm trying to concatenate a sql query string using PHP but not having much luck. I'm processing a form that has dropdown menus for minprice and maxprice (these will always have a value), minsqft and maxsqft dropdown menus (these will also always have a value). The PropertySubtype and Status are OK for this case.

I'm having the problem with the "optional" query terms: beds, waterview, and golf.  Beds is a dropdown menu with integer values BUT I would also like to make this field have some kind of a null value so that it won't affect the query results. Right now I have an empty value passed if the visitor picks "Select All."

For waterview, I'm looking for 'Yes' in the dB and the form's checkbox checked value is 'Yes'

For golf, the dB field contains comma separated values but the value I'm looking for is 'Golf Course Frontage' which is the checked value of the checkbox.
CASE "home":
$query = "SELECT * FROM Listings WHERE ListingPrice BETWEEN $minprice AND $maxprice AND SquareFootage BETWEEN $minsqft AND $maxsqft AND PropertySubtype1 = 'Site Bui' AND Status = 'Active' . "'";
 
if (!empty($beds))
{$query .= " AND Bedrooms = '" . $beds . "'";}
 
if (isset($waterview))
{$query .= " AND WATERVIEW LIKE '" . $waterview . "'";}
 
if (isset($golf))
{$query .= " AND PROPERTIES LIKE '" . $golf";}
 
break;

Open in new window

0
Comment
Question by:Benson_nc
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
2 Comments
 
LVL 7

Accepted Solution

by:
StraySod earned 2000 total points
ID: 24304678
what exactly is your problem? the source you've posted looks ok except of the 2nd and 11th line, which should end like this:
2nd: AND Status = 'Active'";
and
11th: {$query .= " AND PROPERTIES LIKE '" . $golf. "'";}


what is the problem with your if statements? doesn't it work the way you want? what are the results?
how does the form HTML look like?

I'm not exactly sure what should we help you with :)
0
 

Author Comment

by:Benson_nc
ID: 24305755
Thanks for the correction. All is working now.  The only addition I had to make was to put %% around $golf since there was additional text in the dB field different from what I was looking for.
0

Featured Post

VIDEO: THE CONCERTO CLOUD FOR HEALTHCARE

Modern healthcare requires a modern cloud. View this brief video to understand how the Concerto Cloud for Healthcare can help your organization.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

These days socially coordinated efforts have turned into a critical requirement for enterprises.
Nothing in an HTTP request can be trusted, including HTTP headers and form data.  A form token is a tool that can be used to guard against request forgeries (CSRF).  This article shows an improved approach to form tokens, making it more difficult to…
The viewer will learn how to look for a specific file type in a local or remote server directory using PHP.
The viewer will learn how to create a basic form using some HTML5 and PHP for later processing. Set up your basic HTML file. Open your form tag and set the method and action attributes.: (CODE) Set up your first few inputs one for the name and …
Suggested Courses

764 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question