Link to home
Start Free TrialLog in
Avatar of Lee R Liddick Jr
Lee R Liddick JrFlag for United States of America

asked on

determining the date of the last Sunday

I need to figure out what the date is on the Sunday prior to the current day and the date of the Sunday the week before that.  For example, today is Tuesday May 5.  I need to capture the date variable of the Sunday of the current week which in the example would be Sunday, May 3.  Then I also need to capture the week prior to that, so I would need to capture Sunday, April 26.  

Is there even a way to do this?  I'm needing these dates because I have a reporting tool with a drop down of specific periods of time.  For example, in the dropdown I have for choices, This Week, Last Week, This Month, Last Month, This Year, Last Year.  So when the end user chooses one of these periods, it queries the database for that specific period of time.  For example, the end user chooses Last Month.  So in my query, it would get all records from April 1 to April 30.  I have that done...but not sure on how to get the weeks.  

So if the end user chooses This Week, I want the query to give results for records of between May 3 and May 9.  If the end user chooses Last Week, I want the query to give results for records between April 26 and May 2.
Avatar of duncancumming
duncancumming
Flag of United Kingdom of Great Britain and Northern Ireland image

ok, each day of the week has a numeric value, from 1 (Sunday) to 7 (Monday).  I think use that to figure out what day of the week it is, work out what you then need to subtract from the current date to get the previous sunday.  The function you'll need to do that is DayOfWeek(Now())
ASKER CERTIFIED SOLUTION
Avatar of azadisaryev
azadisaryev
Flag of Hong Kong image

Link to home
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
Start Free Trial
SOLUTION
Avatar of _agx_
_agx_
Flag of United States of America image

Link to home
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
Start Free Trial
SOLUTION
Link to home
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
Start Free Trial
... continued:

i.e. for last month:
<cfset lastMonth = dateadd('m', -1, datToday)>
<cfset lastMonthStart = createdate(year(lastMonth), month(lastMonth), 1)>
<cfset lastMonthEnd = createdate(year(lastMonth), month(lastMonth), daysinmonth(lastMonth))>

last year:

<cfset lastYearStart = createdate(year(dateadd('yyyy', -1, datToday)), 1, 1)>
<cfset lastYearEnd= createdate(year(dateadd('yyyy', -1, datToday)), 12, 31)>

Azadi
... Are you getting the impression you can do this with the dateAdd function ? ;-)
Avatar of Lee R Liddick Jr

ASKER

yeah agx...if I would have only known it was this simple.  :)  Just got off of a call, let me take a look at everything.
These were gimme points, weren't they agx?  I'm thinking if I would have thought about it a little bit, I probably would have come up with it, but I need to get this done and a bunch of other stuff before the end of the day and figured I could use some help.  You guys are great!
Thanks to all!
Yep.. but it is nice when the solution is simpler than you think, rather than the other way around ;-)