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key based encrypt, decrypt string for both delphi and C#

Posted on 2009-05-05
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Last Modified: 2012-05-06
This question has been asked and accepted here before, however the answer was not good enough since the encryption was a static shift based on an integer value.
I  am after two simple functions to encrypt and decrypt a string based on a key (salt, string) for both Delphi and C# without using any extra libraries. A simple character shift would be ok as long as it is a key based shift and encrypted string characters are ANSI compatible.
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Question by:mtasking
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9 Comments
 
LVL 26

Expert Comment

by:EddieShipman
ID: 24310714
Sounds like homework, to me...
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Author Comment

by:mtasking
ID: 24310792
You are right Eddie, never thought about that - I should give you 500 points for this answer. I am sure you are a very successful programmer, proficient in several different languages that hates to waste his companys time and money by writing code that lives in somebodys snippet collection and only requires a copy and paste. Let me guess, you are a seasoned developer making lots of money with such comments, arent you? LOL
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LVL 13

Expert Comment

by:ThievingSix
ID: 24310887
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Author Comment

by:mtasking
ID: 24313868
This is a link to file encryption in Delphi.
I  am after two simple functions to encrypt and decrypt a string based on a key (salt, string) for both Delphi and C# without using any extra libraries. A simple character shift would be ok as long as it is a key based shift and encrypted string characters are ANSI compatible.
0
 
LVL 18

Expert Comment

by:Johnjces
ID: 24328782
Maybe this could help you.

I am not an encryption person at all; do not know exactly what is meant by a 'salt' but this might get you headed in a direction you want to go. The 'salt' key might be the 'StartKey' which is made up with some other 'salt' keys.

It does xor character shifts.

John
{*******************************************************
 * Standard Encryption algorithm - Copied from Borland *
 *******************************************************}
function Encrypt(const InString:string; StartKey,MultKey,AddKey:Integer): string;
var
  I : Byte;
begin
  Result := '';
  for I := 1 to Length(InString) do
  begin
    Result := Result + CHAR(Byte(InString[I]) xor (StartKey shr 8));
    StartKey := (Byte(Result[I]) + StartKey) * MultKey + AddKey;
  end;
end;
{*******************************************************
 * Standard Decryption algorithm - Copied from Borland *
 *******************************************************}
function Decrypt(const InString:string; StartKey,MultKey,AddKey:Integer): string;
var
  I : Byte;
begin
  Result := '';
  for I := 1 to Length(InString) do
  begin
    Result := Result + CHAR(Byte(InString[I]) xor (StartKey shr 8));
    StartKey := (Byte(InString[I]) + StartKey) * MultKey + AddKey;
  end;
end;

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LVL 18

Expert Comment

by:Johnjces
ID: 24328859
PS... this could be the same answer provided in whatever post you were referring to in your original Q. I don't know but links to previously found stuff can be helpful so no one gives you repeat information.

John
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Author Comment

by:mtasking
ID: 24329241
Thanks for your answer, this is certainly a start. I changed it up so it can be used with a string key instead of 3 numbers and tested:

  ShowMessage(Encrypt('123abc', '2kewl'));
  ShowMessage(Decrypt(Encrypt('123abc', '2kewl'), '2kewl'));

Anybody up to translate to C# for point split?
function Encrypt(const InString:string; Salt:string): string;
var
  i : Byte;
  StartKey, MultKey, AddKey: Word;
begin
  Result := '';
  if (Salt = '') then begin
    Result := InString;
  end
  else begin
    StartKey := Length(Salt);
    MultKey := Ord(Salt[1]);
    AddKey := 0;
    for i := 1 to Length(Salt) - 1 do AddKey := AddKey + Ord(Salt[i]);
    for i := 1 to Length(InString) do
    begin
      Result := Result + CHAR(Byte(InString[i]) xor (StartKey shr 8));
      StartKey := (Byte(Result[i]) + StartKey) * MultKey + AddKey;
    end;
  end;
end;
 
function Decrypt(const InString:string; Salt:string): string;
var
  i : Byte;
  StartKey, MultKey, AddKey: Word;
begin
  Result := '';
  if (Salt = '') then begin
    Result := InString;
  end
  else begin
    StartKey := Ord(Salt[1]);
    MultKey := Length(Salt);
    AddKey := 0;
    for i := 1 to Length(Salt) - 1 do AddKey := AddKey + Ord(Salt[i]);
    for i := 1 to Length(InString) do
    begin
      Result := Result + CHAR(Byte(InString[i]) xor (StartKey shr 8));
      StartKey := (Byte(InString[i]) + StartKey) * MultKey + AddKey;
    end;
  end;
end;

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LVL 18

Accepted Solution

by:
Johnjces earned 500 total points
ID: 24329438
I don't guarantee these as perfect C# translations, but again, should be close to help get you started.

I cannot test them so hope you can.

JOhn
public static string Encrypt(string InString, string Salt)
        {
            string result;
            byte i;
            ushort StartKey;
            ushort MultKey;
            ushort AddKey;
            result = "";
            if ((Salt == ""))
            {
                result = InString;
            }
            else
            {
                StartKey = Salt.Length;
                MultKey = (int)(Salt[1]);
                AddKey = 0;
                for (i = 1; i < Salt.Length; i ++ )
                {
                    AddKey = AddKey + (int)(Salt[i]);
                }
                for (i = 1; i <= InString.Length; i ++ )
                {
                    result = result + ((char)((byte)InString[i]) ^ (StartKey >> 8));
                    StartKey = (((byte)result[i]) + StartKey) * MultKey + AddKey;
                }
            }
            return result;
        }
 
        public static string Decrypt(string InString, string Salt)
        {
            string result;
            byte i;
            ushort StartKey;
            ushort MultKey;
            ushort AddKey;
            result = "";
            if ((Salt == ""))
            {
                result = InString;
            }
            else
            {
                StartKey = (int)(Salt[1]);
                MultKey = Salt.Length;
                AddKey = 0;
                for (i = 1; i < Salt.Length; i ++ )
                {
                    AddKey = AddKey + (int)(Salt[i]);
                }
                for (i = 1; i <= InString.Length; i ++ )
                {
                    result = result + ((char)((byte)InString[i]) ^ (StartKey >> 8));
                    StartKey = (((byte)InString[i]) + StartKey) * MultKey + AddKey;
                }
            }
            return result;
        }

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Author Comment

by:mtasking
ID: 24330005
Great, thanks.
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