Solved

Query of distinct values

Posted on 2009-05-07
6
249 Views
Last Modified: 2013-11-27
I have a table that has the following values:
ID     Person      Units
128   Greg        8
129   Greg        10
130   Greg         5
131   Greg         6
131   Greg         4
132   Sally         10
133   Sally         5
133   Sally         8
133   Sally         15

I need to write a query that will sum up by person the number of unique Id's and the total number of units.
In this case, it should show:
     Greg     4 (id's)   33 (units)
     Sally     2 (id's)   38 (units)

The kicker is that the id's are not unique, so I need a count of the unique records for each person , but the sum of the units must contain all of the units.

Thanks




0
Comment
Question by:twands
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 3
  • 2
6 Comments
 
LVL 25

Expert Comment

by:lwadwell
ID: 24332753
Hi twands,

try

SELECT Person, count(distinct ID) as idcnt, SUM(Units)
FROM yourtable
GROUP BY Person

lwadwell
0
 
LVL 75

Expert Comment

by:Aneesh Retnakaran
ID: 24332758
select Person, sum(units) as totl
from urTable
group by Person
0
 

Author Comment

by:twands
ID: 24332813
lwadwell

I have tried your solution, but to my knowledge "count(distinct ID) as idcnt" is not supported in access.  It returns an error.
0
Forrester Webinar: xMatters Delivers 261% ROI

Guest speaker Dean Davison, Forrester Principal Consultant, explains how a Fortune 500 communication company using xMatters found these results: Achieved a 261% ROI, Experienced $753,280 in net present value benefits over 3 years and Reduced MTTR by 91% for tier 1 incidents.

 

Author Comment

by:twands
ID: 24332818
aneeshattingal:
Your solution gives me the person and number of units but not the count of unique record id's.
0
 
LVL 25

Accepted Solution

by:
lwadwell earned 250 total points
ID: 24332838
twands,

OK ... that is a shame ... try this (not very nice I must admit)

SELECT t1.Person, t2.idcnt, SUM(t1.Units)
FROM yourtable t1
INNER JOIN (SELECT v1.Person, COUNT(*) as idcnt FROM (SELECT DISTINCT Person, ID FROM yourtable) v1 GROUP BY v1.Person) t2
ON t1.Person = t2.Person
GROUP BY t1.Person, t2.idcnt

lwadwell
0
 

Author Closing Comment

by:twands
ID: 31579298
Thanks much!  With a few minor tweaks, I was able to incorpoarte your solution into my query and it gives me what I was looking for.
0

Featured Post

Webinar: Aligning, Automating, Winning

Join Dan Russo, Senior Manager of Operations Intelligence, for an in-depth discussion on how Dealertrack, leading provider of integrated digital solutions for the automotive industry, transformed their DevOps processes to increase collaboration and move with greater velocity.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Preparing an email is something we should all take special care with – especially when the email is for somebody you may not know very well. The pressures of everyday working life stacked with a hectic office environment can make this a real challen…
Access developers frequently have requirements to interact with Excel (import from or output to) in their applications.  You might be able to accomplish this with the TransferSpreadsheet and OutputTo methods, but in this series of articles I will di…
Using Microsoft Access, learn some simple rules for how to construct tables in a relational database. Split up all multi-value fields into single values: Split up fields that belong to other things into separate tables: Make sure that all record…
Access reports are powerful and flexible. Learn how to create a query and then a grouped report using the wizard. Modify the report design after the wizard is done to make it look better. There will be another video to explain how to put the final p…

726 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question