SQL IIF Statement in SSMS 2005

I already have a query that returns data that i need for a report in SSMS 2005.  I need to generate a column named 'FeedbackTrue' to the already returned data set.  I want this column to contain only 1's and 0's.  

In Access under query designer, i would have just wrote a formula like FeedBackTrue:=IIF(columnname>=Value, 1,0) and then i would have my column of data.

How do i do this query designer within SQL Server Mgmt Studio 2005 under query designer.

I pasted my current query, and i want to base the new column off the value of the CreatedDate column.
SELECT DISTINCT 
                      TblUsers.PK_Users, TblDepartment_lookup.DepartmentName, TblUsers.FullName, TblFeedback.CreatedDate
FROM         TblDepartment_lookup INNER JOIN
                      TblUsers ON TblDepartment_lookup.PK_Department = TblUsers.FK_Department LEFT OUTER JOIN
                      TblFeedback ON TblUsers.PK_Users = TblFeedback.FK_User
GROUP BY TblDepartment_lookup.DepartmentName, TblUsers.FullName, TblFeedback.CreatedDate, TblUsers.PK_Users
ORDER BY TblDepartment_lookup.DepartmentName, TblUsers.FullName

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szadrogaAsked:
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Aneesh RetnakaranDatabase AdministratorCommented:
FeedBackTrue:=CASE WHEN columnname>=Value  THEN  1  ELSE 0  END
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Guy Hengel [angelIII / a3]Billing EngineerCommented:
FeedBackTrue:=IIF(columnname>=Value, 1,0)

translates in SQL into:

CASE WHEN columnname>=Value THEN  1 ELSE 0 END FeedBackTrue  
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szadrogaAuthor Commented:
Thank you so much!  I couldnt get the syntax right and it was driving me nuts!!!
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Microsoft SQL Server 2005

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