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initialize a dynamic array

Posted on 2009-05-08
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Last Modified: 2012-05-06
I need many 2D Matrices in different dimensions.
I#m working with a dynamic array  2DMatrix_REAL;

How to initialize the dyn. array in an elegant way.

Current solution

      setlength(Amatrix, x,y)

      Amatrix[0,0] := .....     Amatrix[ ,] :=    .......

      takes millions of lines of code.!
      Can I copy the Static array Identity  to a Dynamic Array ?
Identity : array [1..5, 1..5] of Real  =

                         ((  0,    0,    0 , 0   , 0   ) ,

                          (  0 ,   0,    0 , 0   , 0   ) ,

                          (  0,    0,    1 , 0   , 0   ) ,

                          (  0 ,   0,    0 , 0   , 0   ) ,

                          (  0 ,   0,    0 , 0   , 0   ) );

 

 

 

type   2DMatrix_REAL =  array of array of Real;

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Question by:BdLm
6 Comments
 
LVL 19

Accepted Solution

by:
MerijnB earned 500 total points
Comment Utility
you can iterate through it

var i, j: integer;

begin

 setlength(Amatrix, x,y)

 for i := 0 to x - 1 do

  for j := 0 to y - 1 do

   Amatrix[x, y] := 0;

end;

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LVL 31

Expert Comment

by:moorhouselondon
Comment Utility
Couldn't you create a buffer that mapped over the array (using the Absolute directive), then initialise that in code?

From Delphi Help:-

Absolute Addresses
You can create a new variable that resides at the same address as another variable. To do so, put the directive absolute after the type name in the declaration of the new variable, followed by the name of an existing (previously declared) variable. For example,

var
   Str: string[32];
   StrLen: Byte absolute Str;
specifies that the variable StrLen should start at the same address as Str. Since the first byte of a short string contains the string's length, the value of StrLen is the length of Str.

You cannot initialize a variable in an absolute declaration or combine absolute with any other directives.

0
 
LVL 19

Expert Comment

by:MerijnB
Comment Utility
You have to be careful with that since a dynamic array is actually a pointer.
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LVL 8

Author Comment

by:BdLm
Comment Utility
any better solution than this one,

      TFilter3D = array [1..3,1..3] of Real;

      TFilter4D = array [1..4,1..4] of Real;

      TFilter5D = array [1..5,1..5] of Real;

      TFilter6D = array [1..6,1..6] of Real;

      TFilter7D = array [1..7,1..7] of Real;
 
 

const SampleFiler  : TFilter3D  =

                         ((  0 ,   0.2 , 0   ) ,

                          (  0.2,  0.2,  0.2 ) ,

                          (  0 ,   0.2 , 0   ));
 
 
 
 
 
 
 

//  copy static array to dyn. array  dim =6

procedure LoadDynArrayFromStaticArray ( aFilter :  TImageFilterReal;  Dim : Integer; aStaticArray : TFilter6D ); overload;

var  i,j   : Integer;

begin

      setlength(AFilter, dim,dim);
 

      for i := 0 to dim -1  do

        for j := 0 to dim-1 do

             aFilter[i,j] := aStaticArray[i+1,j+1];
 

end;
 

//  copy static array to dyn. array  dim =5

procedure LoadDynArrayFromStaticArray ( aFilter :  TImageFilterReal;  Dim : Integer; aStaticArray : TFilter5D ); overload;

var  i,j   : Integer;

begin

      setlength(AFilter, dim,dim);
 

      for i := 0 to dim -1  do

        for j := 0 to dim-1 do

             aFilter[i,j] := aStaticArray[i+1,j+1];
 

end;
 

//  copy static array to dyn. array  dim =4

procedure LoadDynArrayFromStaticArray ( aFilter :  TImageFilterReal;  Dim : Integer; aStaticArray : TFilter4D ); overload;

var  i,j   : Integer;

begin

      setlength(AFilter, dim,dim);
 

      for i := 0 to dim -1  do

        for j := 0 to dim-1 do

             aFilter[i,j] := aStaticArray[i+1,j+1];
 

end;
 

//  copy static array to dyn. array  dim =3

procedure LoadDynArrayFromStaticArray ( aFilter :  TImageFilterReal;  Dim : Integer; aStaticArray : TFilter3D ); overload;

var  i,j   : Integer;

begin

      setlength(AFilter, dim,dim);
 

      for i := 0 to dim -1  do

        for j := 0 to dim-1 do

             aFilter[i,j] := aStaticArray[i+1,j+1];
 

end;
 
 
 

procedure LoadImageFilterByIndex( aFilterNameIndex : integer;  var  aFilter : TImageFilterReal);

var  i ,j :  Integer;

begin

        case aFilterNameIndex  of
 

        0:   LoadDynArrayFromStaticArray ( aFilter, 3 , BasicBlur );
 

        1:    begin
 

              end;

        2:    begin
 

              end;

        3:    begin
 
 

              end;
 

        else
 
 

        end;
 
 
 

end;

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Expert Comment

by:Pierre Cornelius
Comment Utility
Easiest way is to simply copy the data using move function. see sample:
unit Unit1;
 

interface
 

uses

  Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,

  Dialogs, StdCtrls;
 
 

type

  T2dMatrix_REAL = array[1..5, 1..5] of real;

  T2DMatrix_Rec = record

    Description: string;

    Matrix: T2DMatrix_REAL;

  end;

  TMatrices = array of T2dMatrix_Rec;
 

const
 

  Identity : T2dMatrix_REAL  =

                         ((  1,    2,    3 , 4   , 5   ) ,

                          (  6 ,   7,    8 , 0   , 10  ) ,

                          (  11,   12,   13, 14  , 15  ) ,

                          (  0 ,   0,    0 , 0   , 0   ) ,

                          (  0 ,   0,    0 , 0   , 0   ) );
 
 
 
 
 

type

  TForm1 = class(TForm)

    Button1: TButton;

    procedure Button1Click(Sender: TObject);

  private

    Matrices: TMatrices;

  public

    { Public declarations }

  end;
 

var

  Form1: TForm1;
 

implementation
 

{$R *.dfm}
 

procedure TForm1.Button1Click(Sender: TObject);

var c: char;

    i: integer;

begin

  SetLength(Matrices, 10);

  for c:= 'A' to 'J' do

  begin

    i:= Ord(c) - Ord('A');

    Matrices[i].Description:= c+c+c+c+c;

    move(identity[1,1], matrices[i].Matrix[1,1], SizeOf(T2dMatrix_REAL));

  end;

  if (Matrices[1].Matrix[1,1] = 0) then;

end;
 

end.

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Author Closing Comment

by:BdLm
Comment Utility
may be Delphi does not offer any more compact solution
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