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T-SQL Query Optimization Minimum Distance

Posted on 2009-05-11
Medium Priority
Last Modified: 2012-06-27
I have a table that is a cross join on itself to find the distance between all points.  The structure is basically.

initial table: Parcels
ParcelID, X, Y

the derived distance table is built via the attached code and it's structure is:
ParcelID1, ParcelID2, Distance.

I now need a table that has the following structure:
ParcelID, ClosestNegihbor1,ClosestNegihbor2,...ClosestNegihbor5, Distance1, Distance2...Distance5

There are 37 million records in the derived table.  There are 6130 ParcelID's for which I need to calculate their 5 closest neighbors.  How should I approach building the final output table?

Select	p.parcelID as ParcelID,
		l.parcelID as ParcelID2, 
		) as Distance
into DistanceTable
from liberty p
cross join liberty l 
where p.parcelID <> l.parcelID

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Question by:Paulconsulting

Expert Comment

ID: 24360853
Can you provide the actual structure of the table along with the datatypes of each column? And could you provide some rows from the table for me to better understand your needs?

Accepted Solution

FVER earned 2000 total points
ID: 24362182
The query below should do it.
To boost performance, you should consider adding the row_number data in the distance table using the row_nomber function in the filling query.

NB: in case of equal distance, the query retrieves the parcel with min ParcelId
--query to retreive 5 closest using the curent DistanceTable
select ParcelID, ParcelID2, Distance, ROW_NUMBER() over (partition by ParcelID order by Distance, ParcelID2) as RN
 from DistanceTable
SELECT R1.ParcelID, R1.ParcelID2, R2.ParcelID2, R3.ParcelID2, R4.ParcelID2, R5.ParcelID2, 
                    R1.Distance, R2.Distance, R3.Distance, R4.Distance, R5.Distance
       left join RANK_TABLE R2 on R1.ParcelID=R2.ParcelID and R2.RN=2
       left join RANK_TABLE R3 on R1.ParcelID=R3.ParcelID and R3.RN=3
       left join RANK_TABLE R4 on R1.ParcelID=R4.ParcelID and R4.RN=4
       left join RANK_TABLE R5 on R1.ParcelID=R5.ParcelID and R5.RN=5
--query to compute RN directly in the DistanceTable at build time
Select ParcelID, ParcelID2, Distance,
       ROW_NUMBER() over (partition by ParcelID order by Distance, ParcelID2) as RN
from (
Select	p.parcelID as ParcelID,
		l.parcelID as ParcelID2, 
		) as Distancefrom liberty p
cross join liberty l 
where p.parcelID <> l.parcelID) T
 into DistanceTable

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LVL 15

Expert Comment

ID: 24365001
Ok... I wouldn't use scalar functions to create your table - that must take a long time in itself. There's lots of information out there about why this might be a bad idea.


Why not use SQL 2008, use a geometry type, and put some spatial indexes in place. Then it should be very easy to find the five closest items, because the indexing will help. The query above should then work better, because the system will be better able to find the top 5 closest items.

LVL 75

Expert Comment

by:Anthony Perkins
ID: 24365176
This is what Rob is referring to:
Investigating the new Spatial Types in SQL Server 2008 - Part 1
Investigating the new Spatial Types in SQL Server 2008 - Part 2

Author Closing Comment

ID: 31580381
Excellent!  Exactly what I needed thank you.

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