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generate random number of string with java

Posted on 2009-05-12
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Last Modified: 2013-11-23
i want to generate around 10000 lines of random strings and input it to file in java. Please tell me how to do it. Also tell me how to reach to the end of this file after generating the lines. Also tell me how to find the length of the file and the number of lines in this file. Please do not use any system commands or tail command
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Question by:SunScreenCert
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sundar62 earned 125 total points
ID: 24371689
Please find the code snippet below to generate the random number. you can get the number of lines of the file from the attached link -

http://www.faqs.org/docs/javap/c10/ex-10-2-answer.html

You may modify the code accordingly..
import java.security.SecureRandom;

import java.io.*;
 

public class GUID {
 

   private static SecureRandom s_secureRandom = new SecureRandom();
 

   public static void main(String[] args) throws Exception {
 

	   File file = new File("write.txt");

	   PrintWriter output = new PrintWriter(new BufferedWriter(new FileWriter(file)));

    

	   for (int i = 0; i < 10000 ;i++ )

		   output.println(generate());
 

	   output.close();

	   System.out.println("Your file has been written");

      

    }

  

   /**

    * generate guid from time,addr,hash and rand

    */

   public static String generate() {

      StringBuilder stringBuilder = new StringBuilder();

      int time = (int) System.currentTimeMillis();

      int rand = s_secureRandom.nextInt();

      stringBuilder.append(hexFormat(rand));

      return stringBuilder.toString();

   }
 

   /**

    * get int as 8-char string

    */
 

   private static String hexFormat(int data) {

      StringBuilder stringBuilder = new StringBuilder();

      stringBuilder.append("00000000");

      stringBuilder.append(Integer.toHexString(data));

      return stringBuilder.substring(stringBuilder.length() - 8);

   }
 
 

}

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