Solved

Convert Dictionary foreach  search to Linq

Posted on 2009-05-13
11
927 Views
Last Modified: 2013-12-17
Hi

is it possible to convert this code to use Linq instead?
private bool Exists(string name)
        {
            foreach (ClientData p in _clients.Keys)
            {
                if (p.Id.Equals(name, StringComparison.OrdinalIgnoreCase))
                {
                    return true;
                }
            }
 
            return false;
        }

Open in new window

0
Comment
Question by:AWestEng
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 4
  • 3
  • 3
11 Comments
 
LVL 39

Accepted Solution

by:
abel earned 400 total points
ID: 24377004
Yes, it is (btw, there's a LINQ zone too, you may have more luck there...) Here's a one-liner, but you may want to split it a bit:

private bool Exists(string name)
{
    return (from p in _clients.Keys 
        where p.Id.Equals(name, StringComparison.OrdinalIgnoreCase) 
        select p).FirstOrDefault() != null;
}

Open in new window

0
 
LVL 63

Assisted Solution

by:Fernando Soto
Fernando Soto earned 100 total points
ID: 24377422
Hi AWestEng;

Here is code snippet showing how it can be done using Linq methods.

Fernando
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
 
namespace WindowsFormsApplication13
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }
 
        List<ClientData> _clients = new List<ClientData>();
 
        private void Form1_Load(object sender, EventArgs e)
        {
            ClientData cd = new ClientData() { Id = "John" };
            _clients.Add(cd);
            cd = new ClientData() { Id = "William" };
            _clients.Add(cd);
            cd = new ClientData() { Id = "AWestEng" };
            _clients.Add(cd);
            cd = new ClientData() { Id = "Alice" };
            _clients.Add(cd);
        }
 
        private void button1_Click(object sender, EventArgs e)
        {
            // User types name in text box and copies to name
            string name = textBox1.Text.Trim();
 
            if (!Exists(name))
            {
                MessageBox.Show("Name was NOT found");
            }
            else
            {
                MessageBox.Show("Name was found");
            }
        }
 
        private bool Exists(string name)
        {
            return _clients.Where(c => c.Id.Equals(name, StringComparison.OrdinalIgnoreCase))
                           .Select(c => c.Id == String.Empty ? false : true).FirstOrDefault();
        }
    }
 
    public class ClientData
    {
        public string Id { get; set; }
    }
}

Open in new window

0
 
LVL 1

Author Comment

by:AWestEng
ID: 24377483
sorry FernandoSoto:, I accepted able's reply you where posting yours, I'm sorry m8..
0
Online Training Solution

Drastically shorten your training time with WalkMe's advanced online training solution that Guides your trainees to action. Forget about retraining and skyrocket knowledge retention rates.

 
LVL 63

Expert Comment

by:Fernando Soto
ID: 24377641
Not a problem, that happens. Have a great day.  ;=)
0
 
LVL 39

Expert Comment

by:abel
ID: 24377831
If you want, you can request reopen and split. I won't object to that. FernandoSoto put in quite some effort, though I believe his solution is about the same as what I showed (though slightly more verbose perhaps).
0
 
LVL 63

Expert Comment

by:Fernando Soto
ID: 24377994
No need to do that, it is really not a problem.  ;=)
0
 
LVL 1

Author Closing Comment

by:AWestEng
ID: 31581059
Thx guys,, perfect job
0
 
LVL 63

Expert Comment

by:Fernando Soto
ID: 24395047
Thanks AWestEng and abel.  ;=)
0
 
LVL 1

Author Comment

by:AWestEng
ID: 24395269
No!  Thank you guys! Thx for always put your own time into others problem and help out.
I really appreciate it . :)
0
 
LVL 39

Expert Comment

by:abel
ID: 24396146
you're welcome, both, always around to help (almost)  :)
0

Featured Post

Veeam gives away 10 full conference passes

Veeam is a VMworld 2017 US & Europe Platinum Sponsor. Enter the raffle to get the full conference pass. Pass includes the admission to all general and breakout sessions, VMware Hands-On Labs, Solutions Exchange, exclusive giveaways and the great VMworld Customer Appreciation Part

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

In my previous two articles we discussed Binary Serialization (http://www.experts-exchange.com/A_4362.html) and XML Serialization (http://www.experts-exchange.com/A_4425.html). In this article we will try to know more about SOAP (Simple Object Acces…
Wouldn’t it be nice if you could test whether an element is contained in an array by using a Contains method just like the one available on List objects? Wouldn’t it be good if you could write code like this? (CODE) In .NET 3.5, this is possible…
There's a multitude of different network monitoring solutions out there, and you're probably wondering what makes NetCrunch so special. It's completely agentless, but does let you create an agent, if you desire. It offers powerful scalability …
Do you want to know how to make a graph with Microsoft Access? First, create a query with the data for the chart. Then make a blank form and add a chart control. This video also shows how to change what data is displayed on the graph as well as form…

630 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question