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Inserting Birthday in Database?

Posted on 2009-05-13
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Last Modified: 2012-05-06
I am creating a very simple table which will consist of Users Birtday (month and day only)
i created a Table
create 2 col.
Username  type varchar
Bday type Datetime

now on ASP side i need to be able to insert the birthday to DB.
so i created 3 dropdownlist
1-User 2-Month 3-Day
all of them are populated .

now here is my problem not sure how i can insert it into DB as a DateTime format ... my goal is i need to be able to insert it and then write a simple SQL to show me all upcoming Birthdays for the next month.

Thank you,
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Question by:Raul77
  • 6
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10 Comments
 
LVL 75

Expert Comment

by:Aneesh Retnakaran
ID: 24377245
Hello Raul77,

if you dont want to put the year, use to differernt columns to store the Month and day, you can query the upcoming birth days by using

SELECT *
FROM urTable
WHERE MONTH (Getdate() ) = dobMonth

Regards,

Aneesh
0
 

Author Comment

by:Raul77
ID: 24377291
Hello Aneesh
thanks for the help ,
so i need to create 2 col. in DB , should they be type datetime?

btw i am using MSSQL 2000.

and in case you are wondering this is how i populate my dropdownlist

 DateTimeFormatInfo dtfi = new DateTimeFormatInfo();
        for (int month = 1; month < 13; month++)
        {
            ListItem li = new ListItem();
            li.Text = dtfi.GetMonthName(month);
            li.Value = month.ToString();
            ddlMonth.Items.Add(li);
        }
        for (int i = 1; i < 32; i++)
        {
            ListItem day = new ListItem();
            day.Text = i.ToString();
            day.Value = i.ToString();
            ddlDay.Items.Add(day);
        }

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Author Comment

by:Raul77
ID: 24380488
anyone else has any idea on this?

thanks, i can re-design the table if need be.
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LVL 75

Expert Comment

by:Aneesh Retnakaran
ID: 24380511
You can use a TinyInt for  these , tiny int can store upto 255
0
 

Author Comment

by:Raul77
ID: 24380525
Aneesh:
i have a few problem
1-) i would need 2 months in advanced to show ( previosuly stated 1)
2-) what if todays date is 11/23 2 months in advance with be 11/23 ... how can it know that?
also wouldnt the DAY start playing a role?

if its 11/23 , i dont want to see someones birthday if its on 1/28 ! or if it has passed.

Thanks for the help.
0
 
LVL 75

Expert Comment

by:Aneesh Retnakaran
ID: 24380562

DECLARE @Day tinyint,
@Month tinyint
-- for current month
SELECT NAme, dob_Day, dob_Month
FROM urDOBTable
WHERE dob_day > @day and dob_month = @month
UNION ALL
SELECT NAme, dob_Day, dob_Month --- nextMonth
FROM urDOBTable
WHERE dob_month = CASE WHEN @month =12 THEN 1 ELSE @month END
0
 

Author Comment

by:Raul77
ID: 24386508
thanks Aneesh,
we are almost there, since i need the next 2 months i modified your script abit however now i am getting 2 table, we need to union ALL selects in 1 table

Thanks,

SELECT username, Bday, Bmonth
FROM users
WHERE Bday > 14 and Bmonth = 5
UNION ALL
SELECT username, Bday, Bmonth --- nextMonth
FROM users
WHERE Bmonth = CASE WHEN 5 =12 THEN 1 ELSE 6 END

SELECT username, Bday, Bmonth
FROM users
WHERE Bday < 14 and Bmonth = 7

SELECT username, Bday, Bmonth
FROM users
WHERE Bday > 14 and Bmonth = 5
UNION ALL
SELECT username, Bday, Bmonth --- nextMonth
FROM users
WHERE Bmonth = CASE WHEN 5 =12 THEN 1 ELSE 6 END
 
SELECT username, Bday, Bmonth
FROM users
WHERE Bday < 14 and Bmonth = 7

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LVL 75

Accepted Solution

by:
Aneesh Retnakaran earned 500 total points
ID: 24386625
here you go
 

 

DECLARE @Day tinyint, 
@Month tinyint 
-- for current month 
SELECT UserName, BDay, Bmonth 
FROM Users 
WHERE BDay > @day and Bmonth = @month 
UNION ALL 
SELECT UserName, BDay, Bmonth --- nextMonth 
FROM Users 
WHERE Bmonth = CASE WHEN @month =12 THEN 1 ELSE @month+1 END
UNION ALL 
SELECT UserName, BDay, Bmonth --- nextMonth 
FROM Users 
WHERE Bmonth = CASE WHEN @month =11 THEN 1 
					WHEN @Month =12 THEN 2 
					ELSE @month+2 END

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0
 

Author Comment

by:Raul77
ID: 24386637
i added union and it seem to be working :) thank you Sir.
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Author Closing Comment

by:Raul77
ID: 31581095
Thank you,
0

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