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Selecting and displaying data from multiple tables with a variable

Posted on 2009-05-13
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Last Modified: 2012-05-06
Could use a bit of help, I'm loosing hair over this one....

I have 3 tables of data, and need to return a result from all 3 tables based on a variable and time limit
for example... I need to list all the entries for a client for the past seven days from all 3 db tables.


$client="testing";
$sql = "
SELECT table7.submission_id, table7.employee, table7.client, table_8.submission_id, table8.employee, table8.client, table_9.submission_id, table9.employee, table9.client
FROM table7, table8, table9
WHERE table7.client, table8.client, table9.client 
	LIKE CONCAT('%', $client ,'%') 
	AND date >= (SELECT max(date) - INTERVAL '7' DAY FROM table7.submission_date, table8.submission_date, table9.submission_date)";
 
$result = @mysql_query($sql,$connection) or die(mysql_error());	
 
if( mysql_num_rows( $result ) == 0 ) {print "<p class='error'>You currently have no reports available to you</p>";die;}
else {while( list( $submission_id, $employee, $client, $submission_date, ) = mysql_fetch_array( $result ) ) {
 
echo "
  	<table class='list_table' width='500' cellpadding='1' border='1' cellspacing='1'><tr style='height: 20px; font-size:10px;'>
            <td width='150'>$client</td>
            <td width='45'>$employee</td>
            <td width='45'>$submission_id</td>
            <td width='45'>$submisson_date</td></tr>";

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Question by:piecealava
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5 Comments
 
LVL 9

Expert Comment

by:wellhole
ID: 24379157
In your sql statement you need to indicate how each of the tables are related, such as

where table7.id = table8.id
and table8.name = table9.name
and table7.client = table8.client
and table7.client = table9.client

Also, for WHERE table7.client, table8.client, table9.client

I don't believe you can use a comma like this....... If you indentify how the tables are related, you only need to use ONE of them   table7.client LIKE CONCAT('%', $client ,'%')

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Author Comment

by:piecealava
ID: 24379539
I've  incorporated your suggestions, but it returns 0 results when leaving out the like clause,  
When adding the like clause back in I get an error -- Unknown column 'testing' in 'where clause'

here is my code now... any ideas???
SELECT table7.submission_id, table7.col_4, table7.col_2, table7.submission_date, table8.submission_id, table8.col_4, table8.col_2, table8.submission_date,table9.submission_id, table9.col_2, table9.col_4, table9.submission_date
FROM table7, table8, table9
WHERE table7.col_4 = table8.col_4 
AND table8.col_4 = table9.col_4
AND table7.submission_id = table8.submission_id
AND table8.submission_id = table9.submission_id
AND table7.col_2 = table8.col_2
AND table8.col_2 = table9.col_2
AND table7.submission_date = table8.submission_date
AND table8.submission_date = table9.submission_date
 
AND table7.col_2 
	LIKE CONCAT('%', $client ,'%') 

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Expert Comment

by:wellhole
ID: 24379601
If you're getting 0 results, then its possible you're not linking the tables correctly. As for the 'testing' error, its probably from $client. Try '$client' instead.
0
 

Author Comment

by:piecealava
ID: 24380464
Thanks for the $client fix, that works, but I still cannot get the needed results from multiple tables

How do I get the same results from table8,and table 9 included in the result?  col_2 is the client in all tables.  The code below returns the resluts I want from 1 table.  what's my next step?

$client="testing";
$sql = "
SELECT DISTINCT submission_id, col_4, col_2, submission_date
FROM table7
WHERE DATE_SUB(CURDATE(),INTERVAL 7 DAY) <= submission_date
AND col_2 LIKE ('%' '$client' '%')
	";

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Accepted Solution

by:
wellhole earned 1500 total points
ID: 24381028
Any reason you're using distinct? The next step is to add 1 table at a time and join them based on their relation to each other. So, add table8 and link it to table7 and see if you're getting the results you wanted. Then, move onto table9.

Assuming these tables have 1 to 1 relation, then you should always get the same number of results (unless you have conditions for each table). You can use that as your marker.
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