Solved

Selecting and displaying data from multiple tables with a variable

Posted on 2009-05-13
5
373 Views
Last Modified: 2012-05-06
Could use a bit of help, I'm loosing hair over this one....

I have 3 tables of data, and need to return a result from all 3 tables based on a variable and time limit
for example... I need to list all the entries for a client for the past seven days from all 3 db tables.


$client="testing";

$sql = "

SELECT table7.submission_id, table7.employee, table7.client, table_8.submission_id, table8.employee, table8.client, table_9.submission_id, table9.employee, table9.client

FROM table7, table8, table9

WHERE table7.client, table8.client, table9.client 

	LIKE CONCAT('%', $client ,'%') 

	AND date >= (SELECT max(date) - INTERVAL '7' DAY FROM table7.submission_date, table8.submission_date, table9.submission_date)";
 

$result = @mysql_query($sql,$connection) or die(mysql_error());	
 

if( mysql_num_rows( $result ) == 0 ) {print "<p class='error'>You currently have no reports available to you</p>";die;}

else {while( list( $submission_id, $employee, $client, $submission_date, ) = mysql_fetch_array( $result ) ) {
 

echo "

  	<table class='list_table' width='500' cellpadding='1' border='1' cellspacing='1'><tr style='height: 20px; font-size:10px;'>

            <td width='150'>$client</td>

            <td width='45'>$employee</td>

            <td width='45'>$submission_id</td>

            <td width='45'>$submisson_date</td></tr>";

Open in new window

0
Comment
Question by:piecealava
  • 3
  • 2
5 Comments
 
LVL 9

Expert Comment

by:wellhole
Comment Utility
In your sql statement you need to indicate how each of the tables are related, such as

where table7.id = table8.id
and table8.name = table9.name
and table7.client = table8.client
and table7.client = table9.client

Also, for WHERE table7.client, table8.client, table9.client

I don't believe you can use a comma like this....... If you indentify how the tables are related, you only need to use ONE of them   table7.client LIKE CONCAT('%', $client ,'%')

0
 

Author Comment

by:piecealava
Comment Utility
I've  incorporated your suggestions, but it returns 0 results when leaving out the like clause,  
When adding the like clause back in I get an error -- Unknown column 'testing' in 'where clause'

here is my code now... any ideas???
SELECT table7.submission_id, table7.col_4, table7.col_2, table7.submission_date, table8.submission_id, table8.col_4, table8.col_2, table8.submission_date,table9.submission_id, table9.col_2, table9.col_4, table9.submission_date

FROM table7, table8, table9

WHERE table7.col_4 = table8.col_4 

AND table8.col_4 = table9.col_4

AND table7.submission_id = table8.submission_id

AND table8.submission_id = table9.submission_id

AND table7.col_2 = table8.col_2

AND table8.col_2 = table9.col_2

AND table7.submission_date = table8.submission_date

AND table8.submission_date = table9.submission_date
 

AND table7.col_2 

	LIKE CONCAT('%', $client ,'%') 

Open in new window

0
 
LVL 9

Expert Comment

by:wellhole
Comment Utility
If you're getting 0 results, then its possible you're not linking the tables correctly. As for the 'testing' error, its probably from $client. Try '$client' instead.
0
 

Author Comment

by:piecealava
Comment Utility
Thanks for the $client fix, that works, but I still cannot get the needed results from multiple tables

How do I get the same results from table8,and table 9 included in the result?  col_2 is the client in all tables.  The code below returns the resluts I want from 1 table.  what's my next step?

$client="testing";

$sql = "

SELECT DISTINCT submission_id, col_4, col_2, submission_date

FROM table7

WHERE DATE_SUB(CURDATE(),INTERVAL 7 DAY) <= submission_date

AND col_2 LIKE ('%' '$client' '%')

	";

Open in new window

0
 
LVL 9

Accepted Solution

by:
wellhole earned 500 total points
Comment Utility
Any reason you're using distinct? The next step is to add 1 table at a time and join them based on their relation to each other. So, add table8 and link it to table7 and see if you're getting the results you wanted. Then, move onto table9.

Assuming these tables have 1 to 1 relation, then you should always get the same number of results (unless you have conditions for each table). You can use that as your marker.
0

Featured Post

What Is Threat Intelligence?

Threat intelligence is often discussed, but rarely understood. Starting with a precise definition, along with clear business goals, is essential.

Join & Write a Comment

Introduction Since I wrote the original article about Handling Date and Time in PHP and MySQL (http://www.experts-exchange.com/articles/201/Handling-Date-and-Time-in-PHP-and-MySQL.html) several years ago, it seemed like now was a good time to updat…
Does the idea of dealing with bits scare or confuse you? Does it seem like a waste of time in an age where we all have terabytes of storage? If so, you're missing out on one of the core tools in every professional programmer's toolbox. Learn how to …
It is a freely distributed piece of software for such tasks as photo retouching, image composition and image authoring. It works on many operating systems, in many languages.
You have products, that come in variants and want to set different prices for them? Watch this micro tutorial that describes how to configure prices for Magento super attributes. Assigning simple products to configurable: We assigned simple products…

771 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

9 Experts available now in Live!

Get 1:1 Help Now