asked on

Find image path from string using preg_match ?

I have some text like

$text= 'blah blah .. <img src="http://www.techie-diva.com/com_img.php?ID=2&img=vatican-museums-hall.jpg" alt=""> ..... blah blah .. <img src="http://www.techie-diva.com/com_img.php?ID=5&img=secondimage.jpg" alt="">. .. . .blah blah ... ';

I need to find if image path like <img src="http://www.techie-diva.com/com_img.php....... alt=""> exists.

if exists then I need to retrieve one image 's complete html code back like >
<img src="http://www.techie-diva.com/com_img.php?ID=2&img=vatican-museums-hall.jpg" alt="">

could it be done with preg_match ? how to create pattern of search ?
like ...
Find > from '<img src="http://www.techie-diva.com/com_img.php...' to 'alt="">'

Hube02

Try this,

You'll need to view the source to actually see what is in the array due to the values being image tags.

<?php
  
  $text = 'blah blah .. <img src="http://www.techie-diva.com/com_img.php?ID=2&img=vatican-museums-hall.jpg" alt=""> ..... blah blah .. <img src="http://www.techie-diva.com/com_img.php?ID=5&img=secondimage.jpg" alt="">. .. . .blah blah ... ';
  
  $regex = '/<img.*?com_img\.php[^>]*>/i';
  
  preg_match_all($regex, $text, $matches);
  
  print_r($matches[0]);
  
?>

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amitbravo

ASKER

its not working..

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Hube02

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amitbravo

ASKER

I apologies . I did not open view source to see how print_r works . moreover I do not rules how to create expression .. please let me know how could i study in details how to create expression using * ? kind of stuff..

Hube02

To answer the follow up, I learned Regular Expressions by reading http://oreilly.com/catalog/9780596528126/?CMP=AFC-ak_book&ATT=Mastering+Regular+Expressions%2c+Third+Edition%2c and then practicing a lot. Still learning myself actually.