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How to get number of weeks and days between two dates in Access VBA
Posted on 2009-05-15
I would like code that will show the number of weeks and days between two dates. For example - April 8, 2009 (wed) through May 11, 2009 (Mon) would show 4 weeks 5 days.
The 4 would be stored in a field called weeks and the 5 would be stored in days, or even catenate them as a value "4 weeks 5 days" in a database field. This solution is needed for calendar days; however, it would also be neat to know it on a work week (M-F) type and become 4 weeks and 3 days.
Another way to state this: (This should count the number of Wednesdays [4/15, 4/22, 4/29, 5/06] = 4 WEEKS coming up to May 11 and adds the remaining days to get to that date as days THURS [5/07], FRIDAY[5/08], SAT[5/09], SUN[5/10], MON-[5/11 target date] (5 days) CALENDAR type and a solution for the optional way THURS [5/07], FRIDAY[5/08], MON-[5/11 target date] (3 days) for WORK WEEK type.)
Any ideas and workable sub/function would be great.
The 4 would be stored in a field called weeks and the 5 would be stored in days, or even catenate them as a value "4 weeks 5 days" in a database field. This solution is needed for calendar days; however, it would also be neat to know it on a work week (M-F) type and become 4 weeks and 3 days.
Another way to state this: (This should count the number of Wednesdays [4/15, 4/22, 4/29, 5/06] = 4 WEEKS coming up to May 11 and adds the remaining days to get to that date as days THURS [5/07], FRIDAY[5/08], SAT[5/09], SUN[5/10], MON-[5/11 target date] (5 days) CALENDAR type and a solution for the optional way THURS [5/07], FRIDAY[5/08], MON-[5/11 target date] (3 days) for WORK WEEK type.)
Any ideas and workable sub/function would be great.
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4 Comments
Active 1 day ago
Hello HRISTeam,
Assuming your dates have no time portions...
SELECT Date1, Date2, Int(DateDiff("d", Date1, Date2) / 7) & " weeks " & (DateDiff("d", Date1, Date2) Mod 7) & " days"
FROM SomeTable
Regards,
Patrick
Assuming your dates have no time portions...
SELECT Date1, Date2, Int(DateDiff("d", Date1, Date2) / 7) & " weeks " & (DateDiff("d", Date1, Date2) Mod 7) & " days"
FROM SomeTable
Regards,
Patrick
You could use DateDiff to return the number of days
syntax is
DateDiff("d", firstdate, seconddate)
Given this you can then divide by 7 to get weeks and remainder is days
eg using d1 and d2 as dates
NumberOfWeeks = Round((DateDiff("d", d1, d2) / 7) - 0.5)
NumberOfDays = DateDiff("d", d1, d2) Mod 7
syntax is
DateDiff("d", firstdate, seconddate)
Given this you can then divide by 7 to get weeks and remainder is days
eg using d1 and d2 as dates
NumberOfWeeks = Round((DateDiff("d", d1, d2) / 7) - 0.5)
NumberOfDays = DateDiff("d", d1, d2) Mod 7
try this:
datediff("d",#04-08#,#05-1
datediff("d",#04-08#,#05-1
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