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Api for Domains (PHP)

Posted on 2009-05-15
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Last Modified: 2013-11-10
Hi E's, who known a really free api for check domains (php)?

Regards, JC
0
Comment
Question by:Pedro Chagas
  • 3
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  • 2
  • +1
9 Comments
 
LVL 3

Expert Comment

by:markh789
ID: 24400777
You can make a script to check "http://who.is/whois/somedomain.com/" for the domain, and if it has "somedomain.com appears to be available". Check snippet.

I looked on php.net for fsock stuff, take a look.
<?php

// whois.php

if(isset($_GET['domainname'])) {

$fp = fsockopen("http://who.is/whois/" . $_GET['somedomain'] . "/", 80, $errno, $errstr, 30);

if (!$fp) {

    echo $errstr" . " (" . $errno . ")<br />\n";

} else {

    $out = "GET / HTTP/1.1\r\n";

    $out .= "Host: www.who.is\r\n";

    $out .= "Connection: Close\r\n\r\n";

    fwrite($fp, $out);

    while (!feof($fp)) {

        $data_string = $data_string . fgets($fp, 128);

    }

    fclose($fp);
 

    if(strstr($_GET['domainname'] . " appears to be available", $data_string)) {

         return true;

    } else {

         return false;

    }

}

}

?>

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LVL 3

Expert Comment

by:markh789
ID: 24400780
Sorry, try new attached.
<?php

// whois.php

if(isset($_GET['domainname'])) {

$fp = fsockopen("http://who.is/whois/" . $_GET['somedomain'] . "/", 80, $errno, $errstr, 30);

if (!$fp) {

    echo $errstr . " (" . $errno . ")<br />\n";

} else {

    $out = "GET / HTTP/1.1\r\n";

    $out .= "Host: www.who.is\r\n";

    $out .= "Connection: Close\r\n\r\n";

    fwrite($fp, $out);

    while (!feof($fp)) {

        $data_string = $data_string . fgets($fp, 128);

    }

    fclose($fp);

 

    if(strstr($_GET['domainname'] . " appears to be available", $data_string)) {

         return true;

    } else {

         return false;

    }

}

}

?>

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0
 
LVL 3

Expert Comment

by:markh789
ID: 24400806
This code would be smaller and would be a better method and seems it would be easier to put in,
<?php

function CheckDomain($domainname) {

if(strpos(file_get_contents(http://who.is/whois/' . $domainname), $domainname . ' appears to be available')!== false) {

return true;

} else {

return false;

}

}
 

if(CheckDomain("example.com")) {

 echo "Yes!";

} else {

 echo "No.";

}
 

?>

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LVL 3

Author Comment

by:Pedro Chagas
ID: 24401936
Hi @markh789, your last code show this error:
Parse error: syntax error, unexpected ':' in /home/tags/public_html/teste2.php on line 3
//line 3 is: if(strpos(file_get_contents(http://who.is/whois/' . $domainname), $domainname . ' appears to be available')!== false) {

What is wrong is your last code?

Regards, JC
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LVL 4

Accepted Solution

by:
manavsi earned 250 total points
ID: 24402179
correct the above error as following snippet...
<?

function CheckDomain($domainname) {

if(strpos(file_get_contents('http://who.is/whois/' . $domainname), $domainname . ' appears to be available')!== false) {

return true;

} else {

return false;

}

}

 

if(CheckDomain("google.com")) {

 echo "Yes!";

} else {

 echo "No.";

}
 

?>

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0
 
LVL 4

Expert Comment

by:manavsi
ID: 24402192
but look, when i try the above code.. i get NO for google.com
May be i would recommend you for this file here: Its the Best API i know...

Link: http://www.4shared.com/file/105722518/4d614b3f/enom-2007-04-24tar.html

Chk out the examples too...

HTH
Manavsi
0
 
LVL 108

Assisted Solution

by:Ray Paseur
Ray Paseur earned 250 total points
ID: 24403981
Try this... You may not need an API
<?php // RAY_checkdns.php

error_reporting(E_ALL);
 

// FUNCTION TO CHECK FOR A ROUTABLE DNS

function rout($url)

{
 

// PLUCK OUT THE TLD AND THE DOMAIN

   $x = explode('.', strtolower($url));

   if (!is_array($x)) // MAYBE 'localhost'?

   {

      return FALSE;

   }
 

// SOMETHING LIKE 'http://www.google.com' OR 'www2.atf70.whitehouse.gov'?

   else

   {

      $y   = count($x);

      $dmn = $x[$y-2] . '.' . $x[$y-1];

   }
 

// SEE IF THE DOMAIN.TLD IS ROUTABLE

   if ( checkdnsrr($dmn,"MX") || checkdnsrr($dmn,"A") ) return TRUE;
 

// IF NOT ROUTABLE

   return FALSE;

}
 

// TEST CASES

echo "<br/>Google.com ";

var_dump( rout('Google.com') );
 

echo "<br/>shmedlapp.net ";

var_dump( rout('shmedlapp.net') );

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0
 
LVL 3

Author Comment

by:Pedro Chagas
ID: 24405742
Hi @ray, in your example, in //TEST CASES, if I want do:
//TEST CASES
rout('Google.com');
if (available){
 echo "available";
} else {
echo "not available";
}

Sorry the question, but I don't understand well about "return".
==================================================
For @manavsi, I think your last script work well, for google.com the answer is NO, off course NO because is not available! If I try the domain: "sdgfdshfdhdf.com" the answer is YES, because is available!
So I thing your script work well. Thanks for that.

Regards, JC
0
 
LVL 108

Expert Comment

by:Ray Paseur
ID: 24406532
OK, please tell me a little bit more.  Am I understanding it correctly?  You want to know if a domain is registered or available?

I think this is how I would use that code that I posted earlier (see snippet).

Either function may work well for you, but the built-in PHP function checkdnsrr() does not make your programming dependent on an external service.
if (!rout('Google.com'){ echo "available"; }

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