Solved

How to set value to dropdown list

Posted on 2009-05-16
3
576 Views
Last Modified: 2013-12-13
Hi experts,

I'm new at php. I'm trying to create form that uses some dropdown menu/lists to let the user choose between a handful options. There are also quite a few text fields on the form.
Everything works perfect as long as the user fills in all the fields en lists. When the users clicks on 'submit' without filling in all text boxes en lists, I want to show exactly the same form as it was before pressing the 'submit' button.
This works perfect for all my text boxes, but all lists are reset.

I have collected the values of all contents in the dropdown lists with
$rubriek        =   $_POST["rubriek"];
$rubriek2        =  $_POST["rubriek2"];

When a submit failed, echo $rubriek; shows the correct choice of the user, but the dropdown list shows the first option again.
How can I set the value of the dropdown list to $rubriek??

I tried things like
form.rubriek.text = $rubriek;
of
form.rubriek.value=$rubriek;
but that doesn't do anything.

I can do the trick in Javascript, but that is not what I want.
0
Comment
Question by:NoraWil
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
3 Comments
 
LVL 28

Expert Comment

by:gamebits
ID: 24402914
Some code would help, how do you show the page again are you redirecting to the page? How do you keep track of the value submitted are you using session?

Usually you will have something like this

<select name="whatever">
     if(isset($whatever)){echo "<option value=\"$whatever\">$whatever</option>
    then the regular list of options
</select>
0
 
LVL 2

Accepted Solution

by:
pedro_sland earned 500 total points
ID: 24402919
Use something like this:
<select name="rubrick">
  <option value="1" <?php if($_POST['rubrick'] && $_POST['rubrick'] == 1) echo 'selected'; ?>>One</option>
  <option value="2" <?php if($_POST['rubrick'] && $_POST['rubrick'] == 2) echo 'selected'; ?>>Two</option>
  <option value="3" <?php if($_POST['rubrick'] && $_POST['rubrick'] == 3) echo 'selected'; ?>>Three</option>
</select>

Open in new window

0
 

Author Closing Comment

by:NoraWil
ID: 31582237
Thank you, this does the job.
0

Featured Post

Free Tool: Path Explorer

An intuitive utility to help find the CSS path to UI elements on a webpage. These paths are used frequently in a variety of front-end development and QA automation tasks.

One of a set of tools we're offering as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Since pre-biblical times, humans have sought ways to keep secrets, and share the secrets selectively.  This article explores the ways PHP can be used to hide and encrypt information.
Many old projects have bad code, but the budget doesn't exist to rewrite the codebase. You can update this code to be safer by introducing contemporary input validation, sanitation, and safer database queries.
Learn how to match and substitute tagged data using PHP regular expressions. Demonstrated on Windows 7, but also applies to other operating systems. Demonstrated technique applies to PHP (all versions) and Firefox, but very similar techniques will w…
The viewer will learn how to create and use a small PHP class to apply a watermark to an image. This video shows the viewer the setup for the PHP watermark as well as important coding language. Continue to Part 2 to learn the core code used in creat…

705 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question