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insert newsequentialid

I have a table dbo.Profile with column
ProfileID - type uniqueidentifier, primary key generated by newsequentialid ()

I have to insert porifleID in another table dbo.Service (a foreign key relation)
If it was an identity field, i know scope_identity() or ident_current() works.

But how do I obtain and insert the last inserted uniqueidentifier (ProfileID) from Profile table into Service table?
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Angel02
Asked:
Angel02
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1 Solution
 
Aneesh RetnakaranDatabase AdministratorCommented:
why dont you generate the id before you perform the first insert

declare @x uniqueidentifier
select @x  = newsequentialID()
--now do the inserts
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Aneesh RetnakaranDatabase AdministratorCommented:
sorry that wont work , just use the output feature of sql server 2005

create table #tab  (x uniqueidentifier )
insert into urTable
output inserted.columnName into #Temp
SELECT NewsequentialID()

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Angel02Author Commented:
Thank you for the reply. I knew I had to use output, but I coudn't frame it, neitehr could I from your code. Can you please provide more detail? For example, below is the query

INSERT INTO dbo.[User] (Name, Phone) VALUES ("xyz", "123")
-- This generates the uniqueidentifier for UserID column using newsequentialid ()

Then to Insert into the Service table
--ServiceID is again autogenerated using newsequentialID.

INSERT INTO dbo.Service (UserID) VALUES (??)
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Aneesh RetnakaranDatabase AdministratorCommented:
declare @tab table (userid uniqueidentifier)
INSERT INTO dbo.[User] (Name, Phone)
output inserted.userid into @tab
SELECT 'xyz', '12'

declare @userid uniqueidentifier
select @userid = userid
from @tab
select @userid

if you are using sql server 2005, you need to use a temp table instead of table variable to hold the value of the OUTPUT
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Anthony PerkinsCommented:
>>if you are using sql server 2005, you need to use a temp table instead of table variable to hold the value of the OUTPUT<<

Aneesh,

You may want to double check that.

Anthony
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Angel02Author Commented:
Thanks Aneesh. This works great !

Also, in reagrd to what Anthony said, your code works good enough in SQL 2005 too, which is what I am using.

Thanks all !
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Aneesh RetnakaranDatabase AdministratorCommented:
Thanks Anthony :)
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