Solved

XMl And parsing Document

Posted on 2009-05-19
20
243 Views
Last Modified: 2012-08-14
This line is not executed of GenerateReportAction

 JRXmlDataSource xmlDataSource = new JRXmlDataSource(doc.getDocumentURI(),"/userData M55_USERS_NEW");
 
         
Please help me

/*

 * To change this template, choose Tools | Templates

 * and open the template in the editor.

 */
 

package net.ensode.jasperbook.struts;
 

import java.io.*;

    import javax.xml.parsers.*;

    import org.w3c.dom.*;

    import org.xml.sax.*;
 

    public class BasicDom {

 

        // Parses an XML file and returns a DOM document.

        // If validating is true, the contents is validated against the DTD

        // specified in the file.

       

         public Document parseFile(String fileName) {

        System.out.println("Parsing XML file... " + fileName);

         DocumentBuilder docBuilder;

         Document doc = null;

         DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance();

         docBuilderFactory.setIgnoringElementContentWhitespace(true);

         try {

             docBuilder = docBuilderFactory.newDocumentBuilder();

         }

         catch (ParserConfigurationException e) {

             System.out.println("Wrong parser configuration: " + e.getMessage());

             return null;

        }

         File sourceFile = new File(fileName);

         try {

             doc = docBuilder.parse(sourceFile);

         }

         catch (SAXException e) {

             System.out.println("Wrong XML file structure: " + e.getMessage());

             return null;

         }

         catch (IOException e) {

             System.out.println("Could not read source file: " + e.getMessage());

         }

         System.out.println("XML file parsed");

         return doc;

     }

    }
 

__________________________________________________________________________
 
 

package net.ensode.jasperbook.struts;

import java.io.BufferedInputStream;

import java.io.File;

import java.io.FileInputStream;

import java.io.InputStream;

import java.sql.Connection;

import java.sql.DriverManager;

import java.sql.ResultSet;

import java.sql.SQLException;

import java.sql.Statement;

import java.util.HashMap;

import javax.servlet.ServletContext;

import javax.servlet.ServletOutputStream;

import javax.servlet.http.HttpServletRequest;

import javax.servlet.http.HttpServletResponse;

import javax.sql.DataSource;

import net.sf.jasperreports.engine.JRResultSetDataSource;

import net.sf.jasperreports.engine.JasperCompileManager;

import net.sf.jasperreports.engine.JasperFillManager;

import net.sf.jasperreports.engine.JasperRunManager;
 

import net.sf.jasperreports.engine.data.JRXmlDataSource;

import org.apache.struts.Globals;

import org.apache.struts.action.Action;

import org.apache.struts.action.ActionForm;

import org.apache.struts.action.ActionForward;

import org.apache.struts.action.ActionMapping;

import org.w3c.dom.Document;

public class GenerateReportAction extends Action

{

public ActionForward execute(ActionMapping mapping, ActionForm form,

HttpServletRequest request, HttpServletResponse response)

throws Exception

{
 

     ServletContext application=servlet.getServletContext();

     ServletOutputStream servletOutputStream =response.getOutputStream();
 

     try{
 

/*         File file = new File("C:/Documents and Settings/ashish/My Documents/NetBeansProjects/StrutsJasperXml/build/web/reports/ashish.txt");

         file.createNewFile(); */

         System.out.println("Compiling report...");
 

         JasperCompileManager.compileReportToFile("C:/Documents and Settings/ashish/My Documents/NetBeansProjects/StrutsJasperXml/build/web/reports/RemoteReport.jrxml");

         System.out.println("Compilation Succesfully----------------------->");

       

         BasicDom basicDom=new BasicDom();

      

         Document doc =basicDom.parseFile(application.getRealPath("/reports/userxml.xml"));

//        Document doc =basicDom.parseXmlFile("reports/userxml.xml", false);

         System.out.println("After Parse method_______________->++++++ "+doc.getDocumentURI());

         JRXmlDataSource xmlDataSource = new JRXmlDataSource(doc.getDocumentURI(),"/userData/M55_USERS_NEW");
 

         System.out.println("Filling report...");

         InputStream reportStream=new FileInputStream("C:/Documents and Settings/ashish/My Documents/NetBeansProjects/StrutsJasperCompleteApplication/reports/RemoteReport.jasper");

         System.out.println("ReportStream---------->>>>>>>>>>>>>>>>"+reportStream.toString());

         System.out.println("Done!");

         JasperRunManager.runReportToPdfStream(reportStream,servletOutputStream, new HashMap(),xmlDataSource);

         response.setContentType("application/pdf");

        }catch(Exception e){

            e.printStackTrace();

        }

     finally{

       

        servletOutputStream.flush();

        servletOutputStream.close();

     }

     return mapping.getInputForward();

    }

}

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Comment
Question by:achitaley
  • 10
  • 9
20 Comments
 
LVL 92

Expert Comment

by:objects
ID: 24420841
>  JRXmlDataSource xmlDataSource = new JRXmlDataSource(doc.getDocumentURI(),"/userData M55_USERS_NEW");

that can just be:

 JRXmlDataSource xmlDataSource = new JRXmlDataSource(doc ,"/userData M55_USERS_NEW");

0
 

Author Comment

by:achitaley
ID: 24420882
not taking this line for executing
0
 
LVL 92

Expert Comment

by:objects
ID: 24420895
you can avoid parsing the xml yourself though and just pass the file path directly to the data source

0
 
LVL 92

Expert Comment

by:objects
ID: 24420900
what console output are you getting?

0
 

Author Comment

by:achitaley
ID: 24420910
This is my console outpu

Compiling report...
Compilation Succesfully----------------------->
Parsing XML file... C:\Documents and Settings\ashish\My Documents\NetBeansProjects\StrutsJasperXml\build\web\reports\userxml.xml
XML file parsed
After Parse method_______________->++++++ file:C:/Documents%20and%20Settings/ashish/My%20Documents/NetBeansProjects/StrutsJasperXml/build/web/reports/userxml.xml
0
 
LVL 92

Accepted Solution

by:
objects earned 500 total points
ID: 24420932
did you make the change I suggested above?

or alternatively

 JRXmlDataSource xmlDataSource = new JRXmlDataSource(application.getRealPath("/reports/userxml.xml") ,"/userData M55_USERS_NEW");

0
 

Author Comment

by:achitaley
ID: 24420962
ya i did the changes. after that also its taking the line
0
 

Author Comment

by:achitaley
ID: 24420998
sorry sorry

its not taking the line
0
 
LVL 92

Expert Comment

by:objects
ID: 24421036
that select expression doesn't look right. that should be a valid path

0
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Author Comment

by:achitaley
ID: 24421038
hello expert i did not working plz..............
0
 

Author Comment

by:achitaley
ID: 24421056
select expression means i didnt get

i change the path in every manner but not working..
0
 
LVL 92

Expert Comment

by:objects
ID: 24421095
why don't you know what it should be?
It specifies the data to include

0
 

Author Comment

by:achitaley
ID: 24421152
Actually i read the this from jasper report pdf that
JRXmlDataSource contains other constructors that allow us to send the XML document as an org.w3c.dom document, as a java.io file, or as a String containing a Uniform Resource Identifier (URI)


JRXmlDataSource xmlDataSource = new JRXmlDataSource(doc ,"/userData M55_USERS_NEW");


that why i gave as document as in construtor  so this is not taking
and i want to used for jasper report so that i did the parsing of xml...

if u have any code then please give me its urgent
0
 
LVL 92

Expert Comment

by:objects
ID: 24421162
sorry your right, it would be:

 JRXmlDataSource xmlDataSource = new JRXmlDataSource(new File(application.getRealPath("/reports/userxml.xml")) ,"/userData M55_USERS_NEW");

but you still need to work out what select expression you need

0
 

Author Comment

by:achitaley
ID: 24421234
i dont get it did not executing the line
JRXmlDataSource xmlDataSource = new JRXmlDataSource(new File(application.getRealPath("/reports/userxml.xml")) ,"/userData M55_USERS_NEW");

i printed the one line after this by using system.out.println but its not shows..the output

if u hava any other solution please give me
0
 
LVL 92

Expert Comment

by:objects
ID: 24421263
I do understand that. From what you have said it is inside that method attempting to load the data source
I can't tell you what the select expression is as it is related to your data

0
 

Author Comment

by:achitaley
ID: 24570686
i tried as u told but the program is not working
0
 
LVL 92

Expert Comment

by:objects
ID: 24577737
I pointed out what the problem was, there is no way I can tell you what the select expression should be. Only you can determine that.
0
 

Author Closing Comment

by:achitaley
ID: 31582944
not a proper solution but some clue  i got from this Thanks
0

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