Solved

"Missing argument 1 for function" error in PHP

Posted on 2009-05-19
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Last Modified: 2013-12-12
I haven't posted the whole page's code but I will if I need to. I've just included all the parts related to this function.

I'm trying to make a function (funhc) to display the contents of an array later in the page. But when I try the code, I get the following error:
Warning: Missing argument 1 for funhc(), called in test3.php on line 338 and defined in test3.php on line 308

I have 5 different functions that work similarly and I receive the error on all of them. Could anyone help me and point out where my mistake is?
<?php do { ?>

  <?php

				

//tests to see if the last change value is empty (therefore never set)

if (isset($row_taskshc['update'])) {

				

$thisday = date("Y-m-d");

						

//sets the last change date to a variable $date

$date = $row_taskshc['update']; 
 

//format the date for mktime() function -- you need day, month, year

$year = substr($date, 0,4); 

$month = substr($date, 5, 2); 

$day = substr($date, 8, 2); 
 

//sets the frequency to a variable $freq

$freq = $row_taskshc['freq'];
 

//sets the variable to hold the new date. Calculates the new date by 

//evaluating the lastchange date and adding the frequency amount measured in months

$new_datecar = date("Y-m-d", mktime(0, 0, 0, $month +$freq, $day , $year)); 
 

date_diff("$thisday", "$new_datecar");

						

							

if ($ndays <= 15) {

$arrhc[] = array('task' => $row_taskshc['task'], 'adate' => $new_datecar); 

 }		

}

} while ($row_taskshc = mysql_fetch_assoc($taskshc)); 
 

function funhc($arrhc) {

if(empty($arrhc))

   {     return false;   }

	foreach($arrhc as $element) 	{

	$hc_taskelm = $element["task"];

	$hc_dateelm = $element["adate"];

	echo "<b>$hc_taskelm</b> is due on <b>$hc_dateelm</b><br /><br />";

	}

	}
 

funhc();

?>

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Question by:kentcommunications
3 Comments
 
LVL 7

Accepted Solution

by:
tg_wilk earned 125 total points
Comment Utility
If you want to be able to omit some arguments, try assigning the default value. Furthermore, checking for array seems more appropriate then checking if the argument is empty.
function funhc($arrhc = NULL) {

if(!is_array($arrhc))

   {     return false;   }

        foreach($arrhc as $element)     {

        $hc_taskelm = $element["task"];

        $hc_dateelm = $element["adate"];

        echo "<b>$hc_taskelm</b> is due on <b>$hc_dateelm</b><br /><br />";

        }

}

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0
 
LVL 34

Assisted Solution

by:Beverley Portlock
Beverley Portlock earned 125 total points
Comment Utility
Your mistake is that you are calling funhc like this

funhc();

rather than like this

funhc( $someVariableOrOther );

Either pass a variable or alter the function definition as tg_wilk has outlined.
0
 

Author Closing Comment

by:kentcommunications
Comment Utility
Works correct now. A big thanks to both of you!
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