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Using a Wildcard with a Parameter

Posted on 2009-05-20
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Last Modified: 2012-05-07
I am writing a report that will generate a list of survey recipients.  I have two parameters setup: one for the bank acronym and one for job title.  My problem is that, if the user enters only "Teller" in the parameter, it will only return Tellers.  However, there are job titles like Teller Supervisor and FSR/Teller that should also be returned.  I have tried using {Imaging.job_code} like "*{?Job Title}*" but no results are returned with this.  What other way can I use a wildcard with this parameter to get what I'm needing?


{@Status} = "A" and
not isnull ({Imaging.NovellID}) and
{@JobTitle} and
(if {?Bank Acronym} = "*" then true
    else {@Bank} = {?Bank Acronym}) and
{Imaging.job_code} like {?Job Title}

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Question by:tpomeroy
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7 Comments
 
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Accepted Solution

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mlmcc earned 125 total points
ID: 24433523
Try

{Imaging.job_code} like "*" & {?Job Title} & "*"

mlmcc
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Author Comment

by:tpomeroy
ID: 24433565
When I used this, I received this error message:  "This array must be subscripted.  For example: Array [i]."
error.bmp
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Author Comment

by:tpomeroy
ID: 24433686
Okay, I changed the "allow multiple values" in the parameter to False and the error went away.  However, the users really need the ability to enter multiple job titles.  Anyway around that?
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LVL 101

Expert Comment

by:mlmcc
ID: 24434107
Not easily that I can think of.

Can you populate the parameter with valid values so they can choose all the ones they want?

mlmcc
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Author Comment

by:tpomeroy
ID: 24434541
I could but there are hundreds of them.  I will try that, though.
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LVL 101

Expert Comment

by:mlmcc
ID: 24435011
You can use the ability to add them from the table rather than having to add them.

If the user enters *Teller* as a value along with another value does it work if you use

{ReportField} LIKE {?Param}

mlmcc
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Author Comment

by:tpomeroy
ID: 24435121
No it does not.
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