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Returning Ref_cursor to dataview

Posted on 2009-05-20
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Last Modified: 2013-11-07
I am trying to get the data grid (MyDataGrid) to populate.  I run the page with no errors.  Just for grins, I sent an invalid Oracle command, and sure enough, I got an oracle error returned - So I know the code is passing through to the Oracle DB.

I can't get the datagrid to populate/draw though.  I've tested my Stored Procedure otherwise (via SQL/Plus and Excel VBA) and it works fine.

Can somebody help me understand why MyDataGrid isn't showing up on my aspx page?

<%@ Page Language="c#" %>
<%@ import Namespace="System.Data" %>
<%@ import Namespace="Oracle.DataAccess.Client" %>
<%@ import Namespace="System.Data.OleDb" %>
<%@ Assembly Name="System.Data.OracleClient, Version=2.0.0.0, Culture=neutral, PublicKeyToken=B77A5C561934E089" %>
<script runat="server">
 
    protected void Page_Load(Object sender, EventArgs e)
    
    {
    
      OracleConnection con = new OracleConnection("data source=myDatabase;user id=MyuserID;password=myPass;");
    
      con.Open();
    
      OracleCommand cmd = new OracleCommand("Pkg_CPU_Reports.Report_CPU_Histogram",con);
    
      OracleParameter oparam = cmd.Parameters.Add("ResultCursor", OracleDbType.RefCursor);
    
      oparam.Direction = ParameterDirection.Output;
    
       cmd.CommandType = CommandType.StoredProcedure;
    
      OracleDataAdapter adapter = new OracleDataAdapter(cmd);
    
      DataSet myset = new DataSet("ResultCursor");
    
      adapter.Fill(myset);
	  
	  DataGrid MyDataGrid = new DataGrid();
    
      MyDataGrid.DataSource=myset;
    
       MyDataGrid.DataBind();	
 
    }
</script>
<html>
 
 
 
<body>
 
<H1>Result Set</H1>
 
<form runat="server">
 
<asp:datagrid id="MyDataGrid" runat="Server"/>
 
</form>
 
</body>
 
</html>

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Question by:tscottt
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6 Comments
 
LVL 96

Expert Comment

by:Bob Learned
ID: 24441290
How many DataTable and rows does the DataSet have?
0
 
LVL 1

Author Comment

by:tscottt
ID: 24442762
About 10.
0
 
LVL 96

Expert Comment

by:Bob Learned
ID: 24446378
You didn't define any columns for the DataGrid.  If you are using ASP.NET 2.0, then I would suggest using the GridView, which can auto-generate columns from the data source.
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LVL 1

Author Comment

by:tscottt
ID: 24446981
You're a champ for helping me!  I changed it to a GridView, but it still doesn't show a control (much less populate it with data).

As an experiment I changed : asp:GridView id="MyDataGrid"

to

asp: GridView id="nothing really"

And it behaved the same.  It's as if the MyDataGrid binding in the C## inline script isn't being recognized by the ASP:GridView.

 I also tried explicitly setting DataSourceID="myset" (the variable from the script) and DataSourceID="MyDataGrid", and neither of those worked.  At least they threw errors, though.

I'm probably missing something simple about how to bind my asp control to the control of the same name in the script.
0
 
LVL 96

Expert Comment

by:Bob Learned
ID: 24450411
Set the GridView's AutoGenerateColumns property to True.  DataSourceID is used with an SqlDataSource, ObjectDataSource, XmlDataSource, etc.
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Accepted Solution

by:
tscottt earned 0 total points
ID: 24456557
I found the problem.  I was declaring the datagrid (or, in more recent code, the dataview) in the inline C# script - Line 30 in the code above. That's a no-no, as it goes out of scope.

Thanks for keeping me plugging away. :)
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