parse xml with python

i need to read in an xml file and find several attributes in it. For example i need to get the ip address and service name IIS Admin out of this xml:
<computer>
...
 <network>
  <adapter>
   <ip address="192.168.1.13" subnetmask="255.255.255.0" />
  </adapter>
 </network>
...
 <services>
  <service name="IIS Admin" startmode="Auto" started="True" startname="LocalSystem" />
 </services>
....
</computer>
bman87Asked:
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ghostdog74Commented:
you should use a XML parser, eg PyXML. However, if your request is just extract these 2 information, just simple string manipulation will do



for line in open("xmlfile"):
    if "</computer" in line: f=0
    if "<computer>" in line: f=1
    if f :
        if "<ip address" in line:
            ip=line.split()[1].split("=")[-1]
            print ip.replace('"',"")
        if "<service name" in line:
            service=line.split('" ')[0].split("=")[-1]
            print service.replace('"',"")

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bman87Author Commented:
thanks for that solution. It didn't work straight up, but i modified the code so it does.

cheers

xmldoc = open('server.xml','r')
 
for line in xmldoc:
    line = line.lstrip()
    line = line.split('"')
    if "<ip address=" in line[0]:
        print line[1]
    if "<service name=" in line[0]:
        print line[1]

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