Solved

hides more than 1 table from displaying in the dropdown.

Posted on 2009-06-27
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Last Modified: 2012-05-07
this code below hides 1 table from the database named field_types and displays the other tables in a dropdown. i want to hide one more table that should not be displayed in the dropdown. please help me.

otherwise for 1 table, the code is working exactly fine.
i think we need to do something on line 8
<select onchange="changeTargetURL(this);" action="default.php">

        <option targetURL="" selected="selected">Select</option>

        <option targetURL="new.php">create new</option>

		<option>---------------</option>

		<?php

			$res = mysql_query("show tables") or die(mysql_error());

			while ($row = mysql_fetch_array($res)){

			   if ($row[0] == 'field_types') continue;

			   $my_tables[] = $row[0];

			}

			foreach ($my_tables as $tablename){			

		?><option targetURL="<?php echo $tablename.".php"; ?>"><?php echo $tablename; ?></option><?php 			

		} ?>

</select>

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Question by:designersx
  • 2
2 Comments
 
LVL 8

Expert Comment

by:fcardinaux
ID: 24727214
Put all the tables you need to hide in an array, and do this:

<select onchange="changeTargetURL(this);" action="default.php">

        <option targetURL="" selected="selected">Select</option>

        <option targetURL="new.php">create new</option>

                <option>---------------</option>

                <?php

                        $tables_to_hide = array('field_types', 'the_other_table');

                        $res = mysql_query("show tables") or die(mysql_error());

                        while ($row = mysql_fetch_array($res)){

                           if (in_array($row[0], $tables_to_hide) continue;

                           $my_tables[] = $row[0];

                        }

                        foreach ($my_tables as $tablename){                     

                ?><option targetURL="<?php echo $tablename.".php"; ?>"><?php echo $tablename; ?></option><?php                  

                } ?>

</select>

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LVL 8

Accepted Solution

by:
fcardinaux earned 250 total points
ID: 24727218
Sorry, I forgot a parenthesis in my previous code:

<select onchange="changeTargetURL(this);" action="default.php">

        <option targetURL="" selected="selected">Select</option>

        <option targetURL="new.php">create new</option>

                <option>---------------</option>

                <?php

                        $tables_to_hide = array('field_types', 'the_other_table');

                        $res = mysql_query("show tables") or die(mysql_error());

                        while ($row = mysql_fetch_array($res)){

                           if (in_array($row[0], $tables_to_hide)) continue;

                           $my_tables[] = $row[0];

                        }

                        foreach ($my_tables as $tablename){                     

                ?><option targetURL="<?php echo $tablename.".php"; ?>"><?php echo $tablename; ?></option><?php                  

                } ?>

</select>

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0

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