SQL Custom Sort Order

I have a table column 'STATUS' with the following possible Data.
STATUS
========
Active
Inactive
Cancelled
Closed
Pending

I want to Sort the table, but placing Closed on top, and Cancelled last, the other Status type should be Sorted by a Date column.

Is it possible to achieve this in SQL? I'm using SQL 2005.

SELECT * from TABLE_A ORDER BY (Closed on top, Cancelled below, others by Date)

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dennisdominicAsked:
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Aneesh RetnakaranDatabase AdministratorCommented:
SELECT * from TABLE_A
ORDER BY Case WHEN Status = 'Closed' then 99 WHEN 'Cancelled' THEN -99 Else 0 END DESC,[Date]


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dennisdominicAuthor Commented:
Fast and Acccurate.
0
pssandhuCommented:
I am assumin you have data column, so you can do something like this:
Select *, CASE WHEN Status = 'Closed' Then Cast('1700-01-01' as Datetime)
                           WHEN Status = 'Cancelled' Then Cast('3000-01-01' as Datetime)
                           ELSE DateCol
                END as SortOrder
From Table_A
Order by CASE WHEN Status = 'Closed' Then Cast('1700-01-01' as Datetime)
                           WHEN Status = 'Cancelled' Then Cast('3000-01-01' as Datetime)
                           ELSE DateCol
                END


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