Solved

Display Results from SQL with a foreach loop

Posted on 2009-06-28
3
738 Views
Last Modified: 2013-12-13
Hey Guys,

I am having an issue with the following SQL Statement. I want to populate my drop down form box with information from my database.

Pretty much I want to have as many options as there are rows in my <select> drop down </select>

What I need pulled from the database is the following <option value="$rows['page_id']>' . $rows['page_title'] . '</option>";

Here is my code:
$sql = "Select * from content";
	//echo $sql . "<br>";
	
	$result= mysql_query($sql);
	
	$num_rows = mysql_num_rows($result);
	$rows = mysql_fetch_array($result);
	//echo "Total rows found is : " . $num_rows;
	
	for($i = 1; $i <= $num_rows; $i++) {
		echo $i;
		foreach ($rows as $page) {
			//echo $page;
			$cmspages = '<option value="' . $rows['page_id'] . '">' . $rows['page_title'] . '</option>';
		}
	}

Open in new window

0
Comment
Question by:George-TCC
3 Comments
 
LVL 143

Accepted Solution

by:
Guy Hengel [angelIII / a3] earned 500 total points
ID: 24734056
this should do better:
$sql = "Select * from content";
      //echo $sql . "<br>";
      
      $result= mysql_query($sql); 
      $i = 0;
      
      $num_rows = mysql_num_rows($result);
      //echo "Total rows found is : " . $num_rows;
      
      while ($row = mysql_fetch_assoc($result))
      {
         $i++;
         $cmspages = '<option value="' . $row['page_id'] . '">' . $rows['page_title'] . '</option>';
         echo $cmspages;
      }

Open in new window

0
 
LVL 7

Expert Comment

by:szewkam
ID: 24734072
well, the easiest way to loop through data set from db is while.
I'm not pretty sure this is what you want, but try :)
<?
$sql = "Select * from content";
        //echo $sql . "<br>";
        
        $result= mysql_query($sql);
        
        $num_rows = mysql_num_rows($result);
        //echo "Total rows found is : " . $num_rows;
        
        while ($rows = mysql_fetch_array($result)
                        //echo $page;
                        $cmspages = '<option value="' . $rows['page_id'] . '">' . $rows['page_title'] . '</option>';
        }

Open in new window

0
 

Author Closing Comment

by:George-TCC
ID: 31597803
Great it works perfectly!

Thanks for that! Enjoy the points - Well earned! :)
0

Featured Post

Free Tool: Port Scanner

Check which ports are open to the outside world. Helps make sure that your firewall rules are working as intended.

One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Author Note: Since this E-E article was originally written, years ago, formal testing has come into common use in the world of PHP.  PHPUnit (http://en.wikipedia.org/wiki/PHPUnit) and similar technologies have enjoyed wide adoption, making it possib…
Nothing in an HTTP request can be trusted, including HTTP headers and form data.  A form token is a tool that can be used to guard against request forgeries (CSRF).  This article shows an improved approach to form tokens, making it more difficult to…
The viewer will learn how to count occurrences of each item in an array.
The viewer will learn how to create and use a small PHP class to apply a watermark to an image. This video shows the viewer the setup for the PHP watermark as well as important coding language. Continue to Part 2 to learn the core code used in creat…

820 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question