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Display Results from SQL with a foreach loop

Posted on 2009-06-28
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Medium Priority
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Last Modified: 2013-12-13
Hey Guys,

I am having an issue with the following SQL Statement. I want to populate my drop down form box with information from my database.

Pretty much I want to have as many options as there are rows in my <select> drop down </select>

What I need pulled from the database is the following <option value="$rows['page_id']>' . $rows['page_title'] . '</option>";

Here is my code:
$sql = "Select * from content";
	//echo $sql . "<br>";
	
	$result= mysql_query($sql);
	
	$num_rows = mysql_num_rows($result);
	$rows = mysql_fetch_array($result);
	//echo "Total rows found is : " . $num_rows;
	
	for($i = 1; $i <= $num_rows; $i++) {
		echo $i;
		foreach ($rows as $page) {
			//echo $page;
			$cmspages = '<option value="' . $rows['page_id'] . '">' . $rows['page_title'] . '</option>';
		}
	}

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Question by:George-TCC
3 Comments
 
LVL 143

Accepted Solution

by:
Guy Hengel [angelIII / a3] earned 2000 total points
ID: 24734056
this should do better:
$sql = "Select * from content";
      //echo $sql . "<br>";
      
      $result= mysql_query($sql); 
      $i = 0;
      
      $num_rows = mysql_num_rows($result);
      //echo "Total rows found is : " . $num_rows;
      
      while ($row = mysql_fetch_assoc($result))
      {
         $i++;
         $cmspages = '<option value="' . $row['page_id'] . '">' . $rows['page_title'] . '</option>';
         echo $cmspages;
      }

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LVL 7

Expert Comment

by:szewkam
ID: 24734072
well, the easiest way to loop through data set from db is while.
I'm not pretty sure this is what you want, but try :)
<?
$sql = "Select * from content";
        //echo $sql . "<br>";
        
        $result= mysql_query($sql);
        
        $num_rows = mysql_num_rows($result);
        //echo "Total rows found is : " . $num_rows;
        
        while ($rows = mysql_fetch_array($result)
                        //echo $page;
                        $cmspages = '<option value="' . $rows['page_id'] . '">' . $rows['page_title'] . '</option>';
        }

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Author Closing Comment

by:George-TCC
ID: 31597803
Great it works perfectly!

Thanks for that! Enjoy the points - Well earned! :)
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