Solved

How to sum a sub_total amount?

Posted on 2009-06-30
5
287 Views
Last Modified: 2012-05-07
Hi

The following query show this result:

Cash      Cash                           USD      0      4000.00      0
BOA      Bank (Saving)      USD      7      3000.00      0
Cash      Cash                           AUD      0      -10000.00      0
BOA      Bank (Saving)      AUD      1      -5000.00      0

In the last column, 0 as sub_total_amount, actually I want to show the sub-total of total_amount of a currency.

In the above example, the expected result would be:

Cash      Cash                           USD      0      4000.00      0
BOA      Bank (Saving)      USD      7      3000.00      7000
Cash      Cash                           AUD      0      -10000.00      0
BOA      Bank (Saving)      AUD      1      -5000.00      -15000

How can I write the query?


select g.bankcode, a.type, a.currency, a.accountgroupid, sum(t.amount) as total_amount, 0 as sub_total_amount from alltransaction t 

inner join account a on a.id = t.accountid and a.currency = t.currency 

inner join accountgroup g on g.id = a.accountgroupid 

inner join currency c on c.currency = t.currency 

where a.id > 0 and a.id < 301 and t.currency = a.currency 

group by a.type, a.currency, a.accountgroupid, g.id, g.bankcode order by a.currency, g.id

Open in new window

0
Comment
Question by:techques
  • 3
  • 2
5 Comments
 
LVL 5

Accepted Solution

by:
rizwanidrees earned 50 total points
ID: 24751527
Option - A

select g.bankcode, a.type, a.currency, a.accountgroupid, sum(t.amount) as total_amount, sub_total_amount from alltransaction t
inner join account a on a.id = t.accountid and a.currency = t.currency
inner join accountgroup g on g.id = a.accountgroupid
inner join currency c on c.currency = t.currency
inner join (select a.currency, sum(t.amount) as sub_total_amount from alltransaction t
inner join account a on a.id = t.accountid and a.currency = t.currency
inner join accountgroup g on g.id = a.accountgroupid
inner join currency c on c.currency = t.currency
where a.id > 0 and a.id < 301 and t.currency = a.currency
group by a.currency) s on a.currency=s.currency
where a.id > 0 and a.id < 301 and t.currency = a.currency
group by a.type, a.currency, a.accountgroupid, g.id, g.bankcode order by a.currency, g.id

Option - B

select * from (
select g.bankcode, a.type, a.currency, a.accountgroupid, sum(t.amount) as total_amount, 0 as sub_total_amount from alltransaction t
inner join account a on a.id = t.accountid and a.currency = t.currency
inner join accountgroup g on g.id = a.accountgroupid
inner join currency c on c.currency = t.currency
where a.id > 0 and a.id < 301 and t.currency = a.currency
group by a.type, a.currency, a.accountgroupid, g.id, g.bankcode
UNION ALL
select '' bankcode, '' type, a.currency, 0 accountgroupid, 0 total_amount, sum(t.amount) as sub_total_amount from alltransaction t
inner join account a on a.id = t.accountid and a.currency = t.currency
inner join accountgroup g on g.id = a.accountgroupid
inner join currency c on c.currency = t.currency
where a.id > 0 and a.id < 301 and t.currency = a.currency
group by a.currency ) s order by currency

Option - C

select g.bankcode, a.type, a.currency, a.accountgroupid, sum(t.amount) as total_amount, sub_total_amount from alltransaction t
inner join account a on a.id = t.accountid and a.currency = t.currency
inner join accountgroup g on g.id = a.accountgroupid
inner join currency c on c.currency = t.currency
inner join
(
select 'BOA' bankcode, a.currency, sum(t.amount) as sub_total_amount from alltransaction t
inner join account a on a.id = t.accountid and a.currency = t.currency
inner join accountgroup g on g.id = a.accountgroupid
inner join currency c on c.currency = t.currency
where a.id > 0 and a.id < 301 and t.currency = a.currency
group by a.currency
UNION
select 'CASH' bankcode, 0 currency, 0 sub_total_amount from currency
) s on a.currency=s.currency and g.bankcode=s.bankcode
where a.id > 0 and a.id < 301 and t.currency = a.currency
group by a.type, a.currency, a.accountgroupid, g.id, g.bankcode order by a.currency, g.id

0
 

Author Comment

by:techques
ID: 24751577
Option B does work, but both option A and C have errors:

Column 's.sub_total_amount' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause
0
 

Author Closing Comment

by:techques
ID: 31598635
option B does work, thanks
0
 
LVL 5

Expert Comment

by:rizwanidrees
ID: 24751631
add it in over all group by clause
0
 
LVL 5

Expert Comment

by:rizwanidrees
ID: 24751639
Option - A

select g.bankcode, a.type, a.currency, a.accountgroupid, sum(t.amount) as total_amount, sub_total_amount from alltransaction t
inner join account a on a.id = t.accountid and a.currency = t.currency
inner join accountgroup g on g.id = a.accountgroupid
inner join currency c on c.currency = t.currency
inner join (select a.currency, sum(t.amount) as sub_total_amount from alltransaction t
inner join account a on a.id = t.accountid and a.currency = t.currency
inner join accountgroup g on g.id = a.accountgroupid
inner join currency c on c.currency = t.currency
where a.id > 0 and a.id < 301 and t.currency = a.currency
group by a.currency) s on a.currency=s.currency
where a.id > 0 and a.id < 301 and t.currency = a.currency
group by a.type, a.currency, a.accountgroupid, g.id, g.bankcode, sub_total_amount  order by a.currency, g.id

Option - C

select g.bankcode, a.type, a.currency, a.accountgroupid, sum(t.amount) as total_amount, sub_total_amount from alltransaction t
inner join account a on a.id = t.accountid and a.currency = t.currency
inner join accountgroup g on g.id = a.accountgroupid
inner join currency c on c.currency = t.currency
inner join
(
select 'BOA' bankcode, a.currency, sum(t.amount) as sub_total_amount from alltransaction t
inner join account a on a.id = t.accountid and a.currency = t.currency
inner join accountgroup g on g.id = a.accountgroupid
inner join currency c on c.currency = t.currency
where a.id > 0 and a.id < 301 and t.currency = a.currency
group by a.currency
UNION
select 'CASH' bankcode, 0 currency, 0 sub_total_amount from currency
) s on a.currency=s.currency and g.bankcode=s.bankcode
where a.id > 0 and a.id < 301 and t.currency = a.currency
group by a.type, a.currency, a.accountgroupid, g.id, g.bankcode, sub_total_amount order by a.currency, g.id
0

Featured Post

What is SQL Server and how does it work?

The purpose of this paper is to provide you background on SQL Server. It’s your self-study guide for learning fundamentals. It includes both the history of SQL and its technical basics. Concepts and definitions will form the solid foundation of your future DBA expertise.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Everyone has problem when going to load data into Data warehouse (EDW). They all need to confirm that data quality is good but they don't no how to proceed. Microsoft has provided new task within SSIS 2008 called "Data Profiler Task". It solve th…
Ever wondered why sometimes your SQL Server is slow or unresponsive with connections spiking up but by the time you go in, all is well? The following article will show you how to install and configure a SQL job that will send you email alerts includ…
Using examples as well as descriptions, and references to Books Online, show the different Recovery Models available in SQL Server and explain, as well as show how full, differential and transaction log backups are performed
Via a live example, show how to setup several different housekeeping processes for a SQL Server.

867 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

18 Experts available now in Live!

Get 1:1 Help Now