SQL grouping question

I have a table with these fields.  (item_num, location, and value)  

Each item_num might have many entries, each with a different location for the item.

Only one of the item locations should have a value of true (1).  All others should have
a value of false (0).  This lets me know the primary location for the item.  All the other
locations for that item will have a 0 and be secondary locations.

What I want to know is which item_num (item numbers) have all location values of 0 and none with 1.

So:

Show me all item_num where there is no 1 value set for any of the locations.

Can someone tell me the SQL statement for this please?  
jstorm13Asked:
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Patrick MatthewsCommented:
Assuming that [value] is a bit data type...

SELECT item_num
FROM SomeTable
GROUP BY item_num
WHERE MAX(CAST([value] AS int)) = 0
0
Patrick MatthewsCommented:
If [value] is already [tiny][small]int, then this simpler construction should work:

SELECT item_num
FROM SomeTable
GROUP BY item_num
WHERE MAX([value]) = 0
0
jstorm13Author Commented:
It complains about putting a Where after a group by.

If I revers the group by and where then it is in proper order however i get the following error.

An aggregate may not appear in the WHERE clause unless it is in a subquery contained in a HAVING clause
0
ralmadaCommented:
SELECT item_num
FROM SomeTable
GROUP BY item_num
having MAX([value]) = 0
0

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jstorm13Author Commented:
That worked ralmada Thanks.
0
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Microsoft SQL Server 2005

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