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SQL grouping question

Posted on 2009-07-01
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Last Modified: 2012-05-07
I have a table with these fields.  (item_num, location, and value)  

Each item_num might have many entries, each with a different location for the item.

Only one of the item locations should have a value of true (1).  All others should have
a value of false (0).  This lets me know the primary location for the item.  All the other
locations for that item will have a 0 and be secondary locations.

What I want to know is which item_num (item numbers) have all location values of 0 and none with 1.

So:

Show me all item_num where there is no 1 value set for any of the locations.

Can someone tell me the SQL statement for this please?  
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Question by:jstorm13
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5 Comments
 
LVL 92

Expert Comment

by:Patrick Matthews
ID: 24755927
Assuming that [value] is a bit data type...

SELECT item_num
FROM SomeTable
GROUP BY item_num
WHERE MAX(CAST([value] AS int)) = 0
0
 
LVL 92

Expert Comment

by:Patrick Matthews
ID: 24755933
If [value] is already [tiny][small]int, then this simpler construction should work:

SELECT item_num
FROM SomeTable
GROUP BY item_num
WHERE MAX([value]) = 0
0
 

Author Comment

by:jstorm13
ID: 24755975
It complains about putting a Where after a group by.

If I revers the group by and where then it is in proper order however i get the following error.

An aggregate may not appear in the WHERE clause unless it is in a subquery contained in a HAVING clause
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LVL 41

Accepted Solution

by:
ralmada earned 500 total points
ID: 24755982
SELECT item_num
FROM SomeTable
GROUP BY item_num
having MAX([value]) = 0
0
 

Author Comment

by:jstorm13
ID: 24756010
That worked ralmada Thanks.
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