VBScript error

Why is the following code giving an invalid procedure call or argument error
result = Mid(ThisString, 0, 1)

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dev_venAsked:
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Rey Obrero (Capricorn1)Commented:
you start with 1 not 0

result = Mid(ThisString, 1, 1)
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Patrick MatthewsCommented:
dev_ven said:
>>Why is the following code giving an invalid procedure call or argument error

Because you are telling the function to grab 1 character starting at position zero.  That second argument
has to be a positive integer.
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dev_venAuthor Commented:
I figured that, but when I change it to 1  I get the following error:  Object Required
for the following code:

oaccess.Run PipeToTab("C:\Documents and Settings\lmb04\My Documents\Personal\Test.txt", "C:\Documents and Settings\lmb04\My Documents\Personal\ConvertedTest.txt")  

why do I get that error?

Below is my full code for my base problem.

Function PipeToTab(InputFile As String, OutputFile As String)
Dim ThisString As String
Dim NewString As String
Dim A As Integer
Dim result As String
Open InputFile For Input As #1
Open OutputFile For Output As #2

NewString = ""
Do While Not EOF(1)

Line Input #1, ThisString
For A = 1 To Len(ThisString)
If Mid(ThisString, A, 1) = "|" Then
NewString = NewString & Chr$(9)
Else
NewString = NewString & Mid(ThisString, A, 1)
End If
Next

Print #2, NewString
Loop
End Function
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Rey Obrero (Capricorn1)Commented:
if you are running the codes in an Access application

change this

oaccess.Run PipeToTab("C:\Documents and Settings\lmb04\My Documents\Personal\Test.txt", "C:\Documents and Settings\lmb04\My Documents\Personal\ConvertedTest.txt")  


to

 call PipeToTab("C:\Documents and Settings\lmb04\My Documents\Personal\Test.txt", "C:\Documents and Settings\lmb04\My Documents\Personal\ConvertedTest.txt")  


and use this codes

Sub PipeToTab(InputFile As String, OutputFile As String)
Dim ThisString As String
Dim NewString As String
Dim A As Integer
Dim result As String
Open InputFile For Input As #1
Open OutputFile For Output As #2

NewString = ""
Do While Not EOF(1)

Line Input #1, ThisString
For A = 1 To Len(ThisString)
If Mid(ThisString, A, 1) = "|" Then
NewString = NewString & Chr$(9)
Else
NewString = NewString & Mid(ThisString, A, 1)
End If
Next

Print #2, NewString
Loop
close #1
close #2
End sub



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