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inner selects to pass results back to the originating select statment

mphillip85
mphillip85 asked
on
Medium Priority
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Last Modified: 2012-06-21
I am trying to get a list of tables from a table that stores table names with a where clause that gives me only the tables i need. I have a select for that, but I need to pass the tables to the beginning select statement that needs to take the tablename passed and do a count or where clause to get the data I need.
select count(*) from (select table from tables where ACTIVE = 1) AS t1) where mycolumn = 'UPDATE';
 
I am trying to pass the tables so I can get a count and tablename and update mycolumn to 'UPDATED'
 
I want to select the data first to verify contents before I do an update on the records.

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Top Expert 2012

Commented:
Try it this way:

SELECT  COUNT(*)
FROM    ( SELECT    [table]
          FROM      tables
          WHERE     ACTIVE = 1
        ) AS t1
WHERE   mycolumn = 'UPDATE' ;
 
EugeneZ ZhitomirskySQL SERVER EXPERT
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Commented:
mphillip85:
it  needs your additional clarification:
<I am trying to pass the tables  so I can get a count and tablename and update mycolumn to 'UPDATED'
<I want to select the data first to verify contents before I do an update on the records.>

-----------------------------------------------------------------------------------------------------

check if it can  help ...

select table, count(*)  from tables where ACTIVE = 1  and  mycolumn = 'UPDATE';

update tables
set  mycolumn ='UPDATED'
where  ACTIVE = 1  and  mycolumn = 'UPDATE';
 

...

Author

Commented:
Invalid column name 'mycolumn'.

No matter which example I use it comes back with the error message above.

(select mytable from mytables where mycolumn = 'ACTIVE')
This will give me the list of tables.  

I believe I need a fetch cursor routine.  But I do not want to use one, if I do not have to.
If you can write me a fetch that would accomplish this.  That would help as well.


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Top Expert 2012

Commented:
>>Invalid column name 'mycolumn'.<<
You do realize that is the name of the column as you posted it, right?

Since it is obviously a fake name as is "table" why don't you post the structure of the table and then we can give you a valid query for something that is trivial to accomplish, provided you have the right column/table names, that is.

Author

Commented:
SELECT  COUNT(*)
FROM    ( SELECT    dbtable
          FROM      dbobject
          WHERE     dbcolumn = 'priceindex'
        )
WHERE   priceindex = 'myprice' ;

The inner select have the table names to pull from and each of the tables in the inner select have a column called priceindex
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Top Expert 2012
Commented:
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Author

Commented:
Invalid column name 'priceindex'.

The inner select statement pulls tables that have a column named priceindex

The outer select is not grabbing the table name passed and then checking the priceindex column to see if the where statement matches

the outer select does not pull columns from the table being passed, its still referecing what columns I  pull from the inner select statement
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Top Expert 2012

Commented:
if you cannot post the structure of your table(s) then I am afraid I cannot help you any further.

Good luck.

Author

Commented:
so you are telling me that you do not know why the outer select statement is not retrieving values being passed by the inner select statement?  You said this was simple, in your earlier comment, I guess it is not as simple as you stated.  

I will wait for another person or moderator to help.  I do appreciate you trying to help me.  I then ask you to give me the syntax for a DECLARE CURSOR in place of the select statement or translate to a cursor statement.  You were very snobbish when you said this was trivial.  I dont expect that from someone who wants to help.

There is another genius that said it was not possible to do this in another question I checked.  But you are telling me based on your statements that it is possible.  But, now all I want is a cursor statement to do what I am asking or translate the select statement into a cursor statement for me if you would.  I know that works.  So will you help me with that?

Author

Commented:
since I had to do a group by since there was a count(*) involved.
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Top Expert 2012

Commented:
>>since I had to do a group by since there was a count(*) involved.<<
Huh?  There is no GROUP BY required in the SQL Statement I posted:

SELECT  COUNT(*)
FROM    ( SELECT    dbtable
          FROM      dbobject
          WHERE     dbcolumn = 'priceindex'
        ) d
WHERE   priceindex = 'myprice' ;

If you needed one then perhaps you can enlighten us with your "solution".

Also, if you want help on this site then lose the attitude.

Author

Commented:
I merely responded with what I needed to do.  It was resolved, and I was able to do what I needed to do. So was it really necessary to respond back the way you did.  Get over yourself, life is too short, and there are others out there that are on exchange-experts that really care and are sincere, and not arrogant like yourself.  

So, dont anwer my questions.  I can always find someone else who is better at answering my questions.  If you continue this thread, you are really a piece of work.  Otherwise, drop it, grow up and move on.
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Top Expert 2012

Commented:
You are missing the point.  We are here to help everyone.  You have stated that my answer was not sufficient, please do your part and post your solution so that everyone in this community can learn from it.

Thank you,
Anthony
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Top Expert 2012

Commented:
P.S. If you feel my comments are in any way inappropriate feel free to post a message in Community Support to have a Moderator review the whole thread.

Author

Commented:
my apologies, i thought i had actually made it work like I wanted exactly, but i modified it too much to be the original request.  below is the code that should work, but does not

SELECT  COUNT(*)
FROM    ( SELECT    dbtable
          FROM      dbobject
          WHERE     dbcolumn = 'priceindex'
        ) d
WHERE   d.priceindex = 'myprice' ;
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Top Expert 2012

Commented:
>>below is the code that should work, but does not<<
Can you tell me what does this mean? Do you get:

A. An error message.  If so what is it.
B. The wrong results.  If so what are they and what are the desired results.
C. Something else.
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