Javascript childNodes problem

Hi I will try to explain my problem:

I have a function: getChild() that returns the childnodes of an element exept the child with nodetype == 3.

I have an other function: HasChange() that use getChild() to find the firstChild ( here in var div ) and the second child ( here in var input ) and return if the div.innerHTML and input.value are différent or not.

All works great but when i use the both function in my third function: test() a strange thing happened.
HasChange() return the value expected but I lost the content of editables[i] that becomes undefined.
 So I get an error in the remove_control() function that have lost the argument editables[i].

If i run the function test2() all works great, but i find stupid to save editables[i] in the element var just to escape this strange behavior after the element is passed to HasChange();

Thanks for your help.
Object.prototype.getChild = function getChild(){
	var array = this.childNodes; var Childs = Array(); var j=0;
	for(i=0;i<array.length;i++){ if (array[i].nodeType != 3){ Childs[j] = array[i]; j++; } }
	return Childs;
}
 
function HasChange(element){
	var div = element.getChild()[0].getChild()[0];
	var input = element.getChild()[0].getChild()[1];
	return ( div.innerHTML == input.value ) ? false : true;
}
 
function test(){
	for(i=0; i<editables.length; i++){
		if ( !HasChange(editables[i]) ){ 
			remove_control(editables[i]); 
		}
	}
}
 
function test(){ var element = editables[i];
	for(i=0; i<editables.length; i++){
		if ( !HasChange(editables[i]) ){ 
			remove_control(element); 
		}
	}
}

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AngelbladeAsked:
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Michel PlungjanIT ExpertCommented:
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AngelbladeAuthor Commented:
Okay, for sure this is a better way to do :)

But if I have to use the same way to programm for an other utility, any idea why I lost the element passed to HasChange() in this example?
0
Michel PlungjanIT ExpertCommented:
No.
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