Solved

Windows Mobile equivalent of RegDeleteTree

Posted on 2009-07-02
2
258 Views
Last Modified: 2013-12-21
Related question: http://www.experts-exchange.com/Programming/System/Windows__Programming/MFC/Q_24540030.html

How would I delete a sub-tree of registry values on Windows Mobile 5/6? MSDN says RegDeleteTree is for Vista/2008 only.

Code sample if possible.
0
Comment
Question by:mrjoltcola
2 Comments
 
LVL 24

Accepted Solution

by:
alexey_gusev earned 500 total points
ID: 24765595
0
 
LVL 40

Author Closing Comment

by:mrjoltcola
ID: 31599268
Thanks!
0

Featured Post

Free Tool: ZipGrep

ZipGrep is a utility that can list and search zip (.war, .ear, .jar, etc) archives for text patterns, without the need to extract the archive's contents.

One of a set of tools we're offering as a way to say thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

If you are anything like me, you install many apps on your phone and have your life on it, sometimes literally.  When I bought my current phone, a Samsung Galaxy S5 from Verizon, they were only selling the versions with 16 GB internal.  I didn't rea…
Exception Handling is in the core of any application that is able to dignify its name. In this article, I'll guide you through the process of writing a DRY (Don't Repeat Yourself) Exception Handling mechanism, using Aspect Oriented Programming.
This video will show you how to get GIT to work in Eclipse.   It will walk you through how to install the EGit plugin in eclipse and how to checkout an existing repository.
Although Jacob Bernoulli (1654-1705) has been credited as the creator of "Binomial Distribution Table", Gottfried Leibniz (1646-1716) did his dissertation on the subject in 1666; Leibniz you may recall is the co-inventor of "Calculus" and beat Isaac…

831 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question