Windows Security and Kerberos Question

Hello,

    I'm reviewing the Authentications logs on our network, would it be safe to assume if Kerberos is listed as the protocol used that the user was physically sitting at their desk when logging in?  I notice in some of the log entries Kerberos isn't listed, it's just blank.  Trying to get a better understanding of the logon/logoff i.e. 528, 540 evt ID's.

   If you go to your event log, you'll see that it is normal to have 50 to 100 logon/logoff events in one day's time easily, however I know these are not all on the user, some of these events are a result of the network.  How does one tell, actual user from system/network event?
itsmevicAsked:
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Chris GralikeSpecialistCommented:
Logon proceses :

Advapi                    
Triggered by a call to LogonUser; LogonUser calls LsaLogonUser, and one of the arguments to LsaLogonUser, OriginName, identifies the origin of the logon attempt                                
User32                    
Normal Windows 2000 logon using WinLogon, usually also logged with windows update reboots.

SCMgr                    
Service Control Manager started a service                                

KsecDD                      
Network connections to the SMB server-for example, when you use a NET USE command                                

Kerberos                    
The Kerberos Security Support Provider [SSP] , can be utilized by applications to access remote or local resources using the  session provided KDC keys.

NtlmSsp                    
The NTLM SSP (NT LanManager Security Support provider)  used for instance with NTLM web / cifs authentication. http://en.wikipedia.org/wiki/NTLMSSP

Seclogon                    
Secondary Logon-that is, the RunAs command                                 IIS                     IIS performed the logon; generated when logging on the IUSR_machinename account or when using Digest or Basic authentication

Additional reading
I think this resource is a bit out-dated, but based on this one you might be able to find a newer one ;-)

http://technet.microsoft.com/en-us/library/cc751315.aspx

Hope this is what you where looking for ;)

Rgrds,
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