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PHP Variable in a Loop?

Posted on 2009-07-04
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Last Modified: 2013-12-13
Is it possible to create 100's of variables with a loop?  The loop I'm using really cuts down on the code in the page, but I lose all my variables that I need to reference.  Here is what I was thinking.

if $variable < 365 {
$variablenumber = 1;
$variablename{$$variablenumber} = (variablenumber + 1);
} else {
echo "all done";
}

Is this possible?

So, the result would be these answers:
$variablename1 = 1
$variablename2 = 2
$variablename3 = 3
...
$variablename365 = 365
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Question by:bschwarting
6 Comments
 
LVL 142

Expert Comment

by:Guy Hengel [angelIII / a3]
ID: 24777466
>Is it possible to create 100's of variables with a loop?
why not a plain array?

$variablename = array();
for ($i=1; $i<366; $i++)
{
  $variablename[$i] = $i;
} 
//to show the results_
print_r($variablename);

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LVL 12

Expert Comment

by:kevin_u
ID: 24777480
I assume you've looked at an array... $var[$x].

But this should do what you wanted:
$GLOALS['varname'.$variablenumber] = $variablenumber;

you'll get $varname1 = 1, $varname2 = 2,  
and they are all globals.

http://us3.php.net/manual/en/reserved.variables.globals.php



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LVL 19

Accepted Solution

by:
Michael701 earned 500 total points
ID: 24777492
try this

for ($variablenumber=1; $variablenumber<=365 ;$variablenumber++)
{
  $variablename = 'variablename'.$variablenumber;
  $$variablename = $variablenumber;
}
 
echo "var50=".$variablename50 ."<br />\n";
echo "var72=".$variablename72 ."<br />\n";
echo "var321=".$variablename321 ."<br />\n";

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Author Comment

by:bschwarting
ID: 24777786
I could only get Michaels701 to work.  Thanks all!
0
 
LVL 142

Expert Comment

by:Guy Hengel [angelIII / a3]
ID: 24777789
yes, that code will do what you asked.

however, still curious about the why you need that in your code?
it really looks like you are doing something wrong in your method...
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LVL 1

Author Comment

by:bschwarting
ID: 24777802
angel, I wouldn't doubt it.  I'm just past a beginner on PHP.
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