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What does it means with $this-&gt

Posted on 2009-07-04
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Last Modified: 2012-05-07
Hi:

I see the following code:

mysql_select_db($dbName, $this->dbConn) or die(mysql_error());

in a PHP class.

I don't understand $this-&gt

If you've some idea about this, please help.

Thanks,

Somits
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Question by:somits
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7 Comments
 
LVL 143

Assisted Solution

by:Guy Hengel [angelIII / a3]
Guy Hengel [angelIII / a3] earned 150 total points
ID: 24777553
$this->
refers to the object (calls) itself.




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LVL 8

Accepted Solution

by:
fcardinaux earned 350 total points
ID: 24777652
> is the entity name of the "greater-than" character (http://www.w3schools.com/tags/ref_entities.asp).

So, what you see is this code: :

mysql_select_db($dbName, $this->dbConn) or die(mysql_error());

It has simply been transformed by a character escaping function.
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LVL 8

Expert Comment

by:fcardinaux
ID: 24777658
Apparently the entity name has been transformed in my first sentence by Experts-Exchanges. The first sentence of my comment was:

"& g t ;" is the entity name of the "greater-than" character (http://www.w3schools.com/tags/ref_entities.asp).

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Author Comment

by:somits
ID: 24777673
Hi fcardinaux and angellll:

Thanks a lot for your reply. You give me the answer.

Would you give me some more info if you know?
\
Do you know why people write code in that way, instead explicitly writing $this->?

Is there anything wrong when writing $this->?

Thanks a lot,

Somits
0
 
LVL 143

Expert Comment

by:Guy Hengel [angelIII / a3]
ID: 24777699
>Is there anything wrong when writing $this->?
no. I prefer to use it, that way it's clearer when reading the code that you refer explicitly to a class variable/function.
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LVL 8

Expert Comment

by:fcardinaux
ID: 24777709
Nobody writes code in this way. You're probably viewing it on a website that does something wrong with character escaping functions (http://www.php.net/manual/en/function.htmlspecialchars.php). It happens if you call the escaping function twice on the same string:

$var = '>';

// First time (correct)
$var = htmlspecialchars($var);
echo $var;   // Will send '& gt;' to the browser, which will display > on the webpage

// Second time (one time too many)
$var = htmlspecialchars($var);
echo $var;   // Will send '& amp;gt;' to the browser, which will display '& gt;' on the webpage

0
 

Author Comment

by:somits
ID: 24777725
Hi angellll and fcardinaux:

Thanks so much for your help.

It's clear to me now.

Somits
0

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