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VBA: position of substring in a comma-delimited string

Posted on 2009-07-06
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Last Modified: 2013-11-26
Hi X-perts,

I have a comma delimited string like

mystring = "(number1,number2,number3, number4)

or (2343, 7765, 9928, 3354)

I need a function that returns a relative position of a given number inside that string, i.e.

myFunction(mystring, mynumber)

myFunction(mystring, 2343) = 1

etc.

what is the simplest way of doing this? In php it would take just two lines of code with explode/implode, but I am not sure what is the closest option in VBA.

Please, advise..... it needs to be a very short solution

Thanks
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Question by:andy7789
3 Comments
 
LVL 53

Accepted Solution

by:
Dhaest earned 250 total points
ID: 24783703
Easiest way, with the help of split-function
Sub test()

    MsgBox GetPosition("(2343, 7765, 9928, 3354)", "7765")

End Sub
 

Public Function GetPosition(inString As String, searchString As String) As Integer

    Dim strSplit() As String

    GetPosition = -1

    

    ' removing ( and )

    inString = Replace(inString, "(", "")

    inString = Replace(inString, ")", "")

    strSplit = split(inString, ",")

    For i = 0 To UBound(strSplit)

        If Trim(strSplit(i)) = searchString Then

            GetPosition = i + 1

        End If

    Next i

    

End Function

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0
 
LVL 47

Assisted Solution

by:Wayne Taylor (webtubbs)
Wayne Taylor (webtubbs) earned 250 total points
ID: 24783753
If you are using VBA within Excel, you can use the below function, which also shows usage.

Wayne
Sub test()
 

     Dim mystring As String

     mystring = "(2343, 7765, 9928, 3354)"
 

     MsgBox IndexOf(mystring, "9928") 'will return 3
 

End Sub
 

Public Function IndexOf(strArray As String, item As String) As Integer
 

     Dim arr() As String

     arr = Split(Replace(Replace(Replace(strArray, "(", ""), ")", ""), " ", ""), ",")
 

     Dim v As Variant

     v = Application.Match(item, Application.Transpose(arr), 0)

     If IsError(v) Then

          IndexOf = -1

     Else

          IndexOf = v

     End If
 

End Function

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Author Comment

by:andy7789
ID: 24784092
Thank you
0

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