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VBA: position of substring in a comma-delimited string

Posted on 2009-07-06
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Last Modified: 2013-11-26
Hi X-perts,

I have a comma delimited string like

mystring = "(number1,number2,number3, number4)

or (2343, 7765, 9928, 3354)

I need a function that returns a relative position of a given number inside that string, i.e.

myFunction(mystring, mynumber)

myFunction(mystring, 2343) = 1

etc.

what is the simplest way of doing this? In php it would take just two lines of code with explode/implode, but I am not sure what is the closest option in VBA.

Please, advise..... it needs to be a very short solution

Thanks
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Question by:andy7789
3 Comments
 
LVL 53

Accepted Solution

by:
Dhaest earned 1000 total points
ID: 24783703
Easiest way, with the help of split-function
Sub test()
    MsgBox GetPosition("(2343, 7765, 9928, 3354)", "7765")
End Sub
 
Public Function GetPosition(inString As String, searchString As String) As Integer
    Dim strSplit() As String
    GetPosition = -1
    
    ' removing ( and )
    inString = Replace(inString, "(", "")
    inString = Replace(inString, ")", "")
    strSplit = split(inString, ",")
    For i = 0 To UBound(strSplit)
        If Trim(strSplit(i)) = searchString Then
            GetPosition = i + 1
        End If
    Next i
    
End Function

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LVL 48

Assisted Solution

by:Wayne Taylor (webtubbs)
Wayne Taylor (webtubbs) earned 1000 total points
ID: 24783753
If you are using VBA within Excel, you can use the below function, which also shows usage.

Wayne
Sub test()
 
     Dim mystring As String
     mystring = "(2343, 7765, 9928, 3354)"
 
     MsgBox IndexOf(mystring, "9928") 'will return 3
 
End Sub
 
Public Function IndexOf(strArray As String, item As String) As Integer
 
     Dim arr() As String
     arr = Split(Replace(Replace(Replace(strArray, "(", ""), ")", ""), " ", ""), ",")
 
     Dim v As Variant
     v = Application.Match(item, Application.Transpose(arr), 0)
     If IsError(v) Then
          IndexOf = -1
     Else
          IndexOf = v
     End If
 
End Function

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Author Comment

by:andy7789
ID: 24784092
Thank you
0

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