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Enter a series of number then display largest and smallest entered number

Posted on 2009-07-06
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Last Modified: 2013-11-24
I'm required to wite a program which lets the user enter a series of integers.  Th series will continue until the user enters -99.  The program should display the largest and smallest numbers entered.  My program will display the largest number correctly, however, the smallest number displaying is always -99.  Not sure why the smallest number is not printing.  Any feedback will be appreciated.
import javax.swing.JOptionPane;
import java.util.Scanner;
 
 
public class LargestSmallestNumbers
{
	public static void main (String args[])
	{
		int number = 0;
		int largest = 0;
		int smallest = 0;
		
		Scanner keyboard = new Scanner(System.in);
		
		System.out.println("Enter series of number.  Select -99 to end series");
		System.out.println();
		
			while (number != -99)
			{
				
				number = Integer.parseInt(JOptionPane.showInputDialog("Enter integer"));
				
 
					if (number >= largest)
						largest=number;
					else if (number < largest && smallest >= number)
								smallest=number;
					else
								largest = largest;
								smallest = smallest;
			}
 
				System.out.println("Largest number: " + largest);
				System.out.println("Smallest number: " + smallest);
				
	}
}

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Question by:gkilgore
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by:gkilgore
ID: 24791020
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by:gkilgore
ID: 24809077
I need to write a program which will allow me to enter a series of integers.  The series will continue until -99 has been entered which will end the series.  Based upon the numbers entered, the program should display the largest and smallest numbers.  The program thus far will display the largest number entered however, the smallest number displayed is always -99.  Which is the number used to end the series.  Not sure what I am missing in my program.  Any suggestions?  Thank you!
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Accepted Solution

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gkilgore earned 0 total points
ID: 24850608
Please close this program.  No additional assistance is required.  
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